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3 years ago

Which graph represents the system of inequalities?3x+5y<10x−y≤1

Mathematics

1 answer:

Komok [63]3 years ago

4 0

Answer:

I believe it's the one on the bottom left

Step-by-step explanation:

I'm still taking my test so I'll come back later to tell you if it's correct.

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Complete the table. Original Price Percent of Discount Sale Price $80 20% $

Svetach [21]

Answer:

$64

Step-by-step explanation:

80x.20=16

80-16=64

3 0

3 years ago

-7 2/3 + (-5 1/3) + 8 3/4=? A: 6 7/12 B: -4 5/12 C: -21 11/12 D: 4 2/3

balandron [24]

Its B

Hope this helps!

May I have brainliest please? :D

4 0

3 years ago

Read 2 more answers

Aline with a slope of 2 passes through the point (3,9).

azamat

Answer:

WAP

Step-by-step explanation:

ddhghfd WAP

4 0

3 years ago

Dots sells T-shirts ($3) and shorts ($7). In April, total sales were $520. People bought 2 times as many T-shirts as shorts. How

timofeeve [1]

Let's assume

number of shorts is x

we are given

People bought 2 times as many T-shirts as shorts

so, number of T-shirts is 2*x=2x

Dots sells T-shirts ($3) and shorts ($7)

so, total price of T-shirts $=3*2x$

so, total price of shorts $=7x$

now, we are given

total sales were $520

so,

total price of T-shirts+total price of shorts = total sales

we will get equation

$3*2x+7x=520$

now, we can solve for x

$13x=520$

$x=40$

so,

number of shorts is 40

number of T-shirts is 2*40=80............Answer

7 0

3 years ago

Read 2 more answers

A researcher wishes to estimate the average blood alcohol concentration (BAC) for drivers involved in fatal accidents who are f

Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean BAC = 0.16 g/dL

s = sample standard deviation = 0.080 g/dL

n = sample of drivers = 60

$\mu$ = population mean BAC in fatal crashes

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 90% confidence interval for the population mean, $\mu$ is;

P(-1.672 < $t_5_9$ < 1.672) = 0.90 {As the critical value of t at 59 degrees of

freedom are -1.672 & 1.672 with P = 5%} P(-1.672 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.672) = 0.90

P( $-1.672 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $0.16-1.672 \times {\frac{0.08}{\sqrt{60} } }$ , $0.16+1.672 \times {\frac{0.08}{\sqrt{60} } }$ ]

= [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

7 0

3 years ago