<span>To produce 1000L of mixture the factory will need 657 liters of grade A and 343 liters of grade B. To determine this you have to figure out the percentage of each grade in the mixture. The ratio is 2.3 liters to 1.2 liters. Therefor in this scenario the unit equaling 100% is 3.5 liters. To find the percentage of grade A you divide the amount used by the total amount of the unit 100%:
2.3 divided by 3.5 = .657 (multiply the answer by 100 to get 65.7%).
To find the percentage of grade B you divide the amount used by the total amount of the unit 100%:
1.2 divided by 3.5 = .343 (multiply the answer by 100 to get 34.3%)
To test your answer make sure both percentages add up to 100%:
65.75 plus 34.35 = 100%
To determine how much of grade A and grade B is needed for a set amount of liters you multiply the percentage by the liters needed.
For this situation you multiply 65.7% (when multiplying percentages you need to multiply in decimal form).
For grade A you multiply .657 (65.7%) by 1000 liters = 657 liters
For grade B you multiply .343 (34.3%) by 1000 liters = 343 liters
To test your answer you can use the same addition as you did to test the percentages:
657 liters plus 343 liters = 1000 liters</span>
F(x) = 5cos(1/2x) - 2
g(x) = 5cos(x) - 2
The period for a cosine function is 2pi/k
In the equation the k is located before the variable.
In g(x) we have 5cos (1x) -2
so the period is 2pi/1 or 2pi. This means the length of one full period of cosine will go from 0 to 2pi.
In f(x) we have 5 cos (1/2 x) - 2
so the period is 2pi/ (1/2) which is the same as 2pi * 2 or 4pi.
This means the period for the function is 4pi and the length of one full period of the cosine graph will go from 0 to 4pi.
The length of f(x) will be longer than that of g(x) .
Answer:
−2/1−2x1
Step-by-step explanation:
Answer:
C.112
Step-by-step explanation:
Answer:
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