998994 and 112111
This seems to be the best numbers
Answer:
15813.64 rounded to nearest hundredth
9514 1404 393
Answer:
(a) no
(b) no
Step-by-step explanation:
The two questions are asking essentially the same thing. There is nothing that indicates DC ≅ DB or that AC ≅ AB. One (both) of these conditions is (are) required for ΔBAC to be isosceles, so that AD is both a perpendicular bisector of BC and a bisector of angle BAC.
There is not enough information to answer either question affirmatively.
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
the slope is 0.75
Step-by-step explanation:
you have to find the coordinate of each point then put them in acording to the formula in this case the coordinates are (-2,3) X1 and X2 and (-1,1)y1 and y2
