Area of rectangular board = length (inches) x width (inches) = 12" x 16" = 192 in²
Area of the border is given as 128 in²
Adding the area of the board and the border gives (192 + 128)in² = 320 in²
Set this up as the algebraic equation (x + 12)(x + 16) = 320 and solve for x:
Remember to use the FOIL method, which is multiplying the terms in the order of first, outer, inner, last.
x² + 12x + 16x + 192 = 320
x² + 28x + 192 - 320 = 0
x² + 28x - 128 = 0
solve for the two x values:
(x + 32)(x - 4) = 0, and knowing we only need the positive x value
x = 4 or 4 inches is the width of the border
Answer:
The First one
Step-by-step explanation:
-2 with zero , -1 with zero , zero with 6
etc....
from the diagram you see that.
The answer is C. 1/2
Hope this helps!
Hello!
3 x - 40^0 = 2 x - 10^0
3 x - 1 = 2 x - 1
3 x = 2x
3 x - 2 x = 0
Hence, the answer is 0
I hope this helps, and have a nice day!
let g(x) = x^2+2
let f(x) = 9/x
f(g(x)) is therefore equal to f(x^2 + 2) which is equal to 9/(x^2+2).
