What is the equation of the parabola with focus (0, -3) and directrix y= 2?

Mathematics

1 answer:

yKpoI14uk [10]2 years ago

4 0

Answer:

y = -1/10x^2 -1/2

Step-by-step explanation:

The equation for a parabola with focus (a, b) and directrix y = d is ...

y = 1/(2(b -d))(x -a)² +(b +d)/2

For the given focus and directrix, we have ...

a = 0
b = -3
d = 2
y = 1/(2(-3-2))(x -0)² +(-3+2)/2

Simplified, the equation is ...

y = -1/10x² -1/2

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