Question

Sadie set her watch 2 seconds behind, and it falls behind another 2 seconds every day. Write an equation that shows the relationship between the days since watch was last set d and the seconds behind s.

Answer 1

Answer:

nth day: w:x:(y-2(n-1))

Step-by-step explanation:

Let Original time = w:x:y

Where w is the hours, and x is the minutes, and y is the seconds.

Sadie's time on the first date: w:x:(y-2)

Second day: w:x:(y-4)

Third day: w:x:(y-6)

and so on

nth day: w:x:(y-2(n-1))