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1 year ago

7

edgar rolls two six-sided number cubes. What is the probability that he rolls a 5 on the first cube and a number greater than 4

on the second cube? Use the diagram 1of the sample space to help you.

1 answer:

lara31 [8.8K]1 year ago

5 0

Answer: 2/36= 1/18

Step-by-step explanation:

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What is the answer of 2 1/3 - 2/3 and an estimate pls

Lubov Fominskaja [6]

Answer:

$\frac{5}{3}$ or 1.7 as a decimal (1.6 repeating)

Step-by-step explanation:

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2 years ago

What can i do to be brainiest

grigory [225]

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3 years ago

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Question 3<br> Find the equation of the line joining (-2,4) and (3,7)

otez555 [7]

Answer:

y = (3/5)x+26/5 or 5y = 3x+26

Step-by-step explanation:

Applying,

The equation of a line in two point form

(y₂-y₁)/(x₂-x₁) = (y-y₁)/(x-x₁)............... Equation 1

From the question,

Given: y₂ = 7, y₁ = 4, x₂ = 3, x₁ = -2

Substitute these values into equation 1

(7-4)/[3-(-2)] = (y-4)/(x+2)

3/5 = (y-4)/(x+2)

5(y-4) = 3(x+2)

5y-20 = 3x+6

5y = 3x+6+20

5y = 3x+26

y = (3/5)x+26/5

Hence the equation of the line is y = (3/5)x+26/5 or 5y = 3x+26

7 0

2 years ago

(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

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2 years ago

On a coordinate grid, Ming's house is located 2 blocks to the right and blocks up from (0. 0). Joe's house is located 3 blocks t

kolbaska11 [484]

If o<span>n a coordinate grid, Ming's house is located 2 blocks to the right and (I suppose also 2) blocks up from (0. 0), then the ordered pair that describes the location of Ming's house is (2,2) (moving right 2 units from some point you have to add 2 units to the x-coordinate of the point from which you are moving and moving up 2 units from this point you have to add 2 units to y-coordinate of the point from which you are moving up).
</span>
If Joe's house is located 3 blocks to the right and 2 blocks down from Ming's house, then the ordered pair that describes the location of Ming's house is (2+3,2-2), that is (5,0) <span><span>(moving right 3 units from some point you have to add 3 units to the x-coordinate of the point from which you are moving and moving down 2 units from the point you have to substract 2 units from y-coordinate of the point from which you are moving down)</span>.</span>

3 0

3 years ago