step 1
Find out the slope WX
W(2,-3) and X(-4,9)
m=(9+3)/(-4-2)
m=12/-6
m=-2
step 2
Find out the slope YZ
Y(5,y) and Z(-1,1)
m=(1-y)/(-1-5)
m=(1-y)/-6
m=(y-1)/6
step 3
Remember that
If two lines are perpendicular
then
their slopes are negative reciprocal
that means
(y-1)/6=1/2 -----> because the negative reciprocal of -2 is 1/2
solve for y
2y-2=6
2y=6+2
2y=8
<h2>y=4</h2>
4(5x+25)
5(4x+20)
10(2x+10)
2(10x+50)
20(x+5)
hope this helps
Answer:
9pr = 2q^2
Step-by-step explanation:
28.
px^2 + qx + r = 0
If one root is A then the other root is 2A
We have A + 2A = -q/p and A*2A = r/p
So 3A = -q/p so A = -q/3p and A^2 = r/2p so A = √ (r / 2p)
Equating these 2 equations:-
-q/3p = √(r / 2p)
q^2 / 9p^2 = r / 2p
9p^2r = 2pq^2
9pr = 2q^2 (answer)
Answer:
13 pounds
Step-by-step explanation:
21-12=13
C(x) = 300.
Our question becomes simple: 300 = x^2-40x+610
x^2-40x+610-300 = 0
x^2-40x+310 = 0
Now find the value for x with either the quadratic formula or by factorization.
Let me know how it goes. Giving the full answer won’t help you improve
