First we need to arrange the numbers in this number set from smallest to biggest:17,18,24,27,31,39,42,47,55,65. Then there are 10 numbers in this number set. So when we calculate the median, we need to find the middle two numbers and calculate their average. So the median is (31+39)/2=35. SO the answer is B
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
Answer:
the answer would be 35
Step-by-step explanation:
Answer:
A≈61.94
Just plug it into a calculator
