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klemol [59]
3 years ago
6

PLA HELP ME ASAP FOR 12 and 13 (SHOW WORK!!!!!) + LOTS OF POINts!

Mathematics
1 answer:
jekas [21]3 years ago
4 0
For 12. Neil's mistake was that he didn't combine like terms of both the constant and numbers with both the variable of k. 9 and -8 are both constants so you combine it and get an answer of 1 since 9+ -8 is 1. 12k and k both have the variable of k so you combine it and get 13k. 

The simplified version should be: 13k+1=12k-1

For 13. The third expression would be equivalent to the expression above listed as 12r+6s. The third expression is 4(3r+s)+2s and if you do PEMDAS you will get the same answer. Parentheses, 4 times 3r is 12r and 4 times s is 4s and after that you get 12r+4s+2s. As said before, if they have like terms you combine it so you get 12r+6s and it will equal the same as the one shown above.

Hope this helped you and would love brainiest!  <span />
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6 0
3 years ago
Which of the following is not the same as positive 7?
bekas [8.4K]
Seven units to the left of the 0 on a number line would = -7 thus answer 3 being the correct answer
3 0
3 years ago
Read 2 more answers
The sum of three numbers is 8. The third is 9
Ierofanga [76]

Answer:

→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>

→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>

→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>

Step-by-step explanation:

• let numbers be x, y and z

{ \tt{z = 8y - 9 -  -  - (eqn \: 1)}} \\  \\ { \tt{10x = 8y - 7 -  -  - (eqn \: 2)}} \\  \\ { \tt{x + y + z = 8 -  -  - (eqn \: 3)}}

• from eqn 2, make x the subject:

{ \tt{x =  \frac{8y - 7}{10} }} \\

• substitute all variables in eqn 3:

{ \tt{ \frac{8y - 7}{10}  + y + 8y - 9 = 8}} \\  \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\  \\ { \tt{98y = 177}} \\  \\ { \boxed{ \tt{ \: y = 1.8}}}

• find z

{ \tt{z = 8y - 9}} \\  \\ { \tt{z = 8(1.8) - 9}} \\  \\ { \tt{z = 14.4 - 9}} \\  \\ { \boxed{ \tt{ \: z = 5.4 \: }}}

• find x:

{ \tt{x =  \frac{8(1.8) - 7}{10} }} \\  \\ { \tt{x =  \frac{7.4}{10} }} \\  \\ { \boxed{ \tt{ \: x = 0.74 \: }}}

Rounding to nearest value:

{ \boxed{ \rm{x = 1}}} \\ { \boxed{ \rm{y =2 }}} \\ { \boxed{  \rm{z = 5}}}

7 0
2 years ago
Given f(x) = x^3-3 , find f(-2).<br> Show work please
Tasya [4]
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8 0
3 years ago
What is the surface area of this right prism?<br><br> Enter your answer in the box.<br><br> cm²
fomenos

Answer:

<h2>the answer is</h2><h2>166 cm²</h2>

Step-by-step explanation:

we know that

surface area of the prism=2*area of the base+perimeter of the base*height

step 1

find the area of the base

area of the base=length* width

length=5 cm

width=4 cm

area of the base=5*4-----> 20 cm²

step 2

find the perimeter of the base

perimeter=2*[length+width]-----> 2*[5+4]----> 18 cm

step 3

height=7 cm

step 4

find the surface area

surface area of the prism=2*area of the base+perimeter of the base*height

surface area of the prism=2*20+18*7----> 166 cm²

7 0
2 years ago
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