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son4ous [18]
2 years ago
7

In parallelogram MNPQ if m/PQM = 140° find m/MNP.

Mathematics
2 answers:
AysviL [449]2 years ago
5 0

Answer: 140

Step-by-step explanation:

A parallelogram means the sides are parallel, so PQM would have the same angle as MNP since they are opposite, just like NPQ and QMN.

Alex_Xolod [135]2 years ago
3 0

Answer: 140°

Detailed Explanation with Figure:

In a Parallelogram, the Opposite Angles are Equal. Therefore, ∠PQM = ∠MNP, which is equal to 140°.

Here’s the Figure :-

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kodGreya [7K]

Answer:

The simplified form of the given expression is (2x-1).

Step-by-step explanation:

Consider the given expression is

\ln e^{2x-1}

According to the Inverse Properties of In

\ln e^x=x

In the given expression the power of e is (2x-1).

Using the Inverse Properties of In, we get

2x-1

Therefore, the simplified form of the given expression is (2x-1).

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3 years ago
Lee ran a mile in 7 1/3 minutes. His friend Sam ran the same mile in 8 5/9 minutes. How many minutes faster did Lee run? (First
Anna [14]

Answer:

1 2/9 minutes faster

Step-by-step explanation:

Take the larger number and subtract the smaller number

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3 years ago
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4 0
3 years ago
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HELLO!! I NEED HELP! Please show full Solutions. I will mark brainliest for the best answer. Thank you and god bless.
Greeley [361]
((x+2)(x+2))-((x-5)(1))=A

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8 0
3 years ago
insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of
ss7ja [257]

Answer: (13.22\%,\ 19.34\%)

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : \hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628

=16.28\%

Significance level : \alpha= 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Confidence level for population proportion:-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= (13.22\%,\ 19.34\%)

7 0
3 years ago
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