Question

What is the vertical asymptote for the reciprocal of y=8x-4

Answer 1

Answer:

The vertical asymptote for the reciprocal of y=8x-4 is $\frac{1}{2}$

Step-by-step explanation:

Given Equation : $y = 8x-4$

Reciprocal of given equation =$\frac{1}{y}=\frac{1}{8x-4}$

Now to find the vertical asymptote

$\frac{1}{y}=\frac{1}{8x-4}$

Equate denominator to 0

8x-4=0

8x=4

$x=\frac{4}{8}$

$x=\frac{1}{2}$

So, The vertical asymptote is$\frac{1}{2}$

Hence the vertical asymptote for the reciprocal of y=8x-4 is $\frac{1}{2}$