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Brilliant_brown [7]
3 years ago
15

What is the vertical asymptote for the reciprocal of y=8x-4

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer:

The vertical asymptote for the reciprocal of y=8x-4 is \frac{1}{2}

Step-by-step explanation:

Given Equation : y = 8x-4

Reciprocal of given equation =\frac{1}{y}=\frac{1}{8x-4}

Now to find the vertical asymptote

\frac{1}{y}=\frac{1}{8x-4}

Equate denominator to 0

8x-4=0

8x=4

x=\frac{4}{8}

x=\frac{1}{2}

So, The vertical asymptote is\frac{1}{2}

Hence the vertical asymptote for the reciprocal of y=8x-4 is \frac{1}{2}

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3 years ago
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Oksana_A [137]

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log (10x + 200) = log (x²) + log (10)

log (10x + 200) = log (10x²)

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Check for extraneous solutions:

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8 0
3 years ago
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.  Lisa's dog has 4 squeaky toys   
.  the squeaky toys are 2/3 of all the dog's toys

.  let <em>x</em> be number of all dog toys

<em>make an equation</em>
(2/3)<em>x</em> = 4   <em>← solve</em>
x=6

<em>check</em>
2/3 × 6 = 4

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