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Brilliant_brown [7]
2 years ago
15

What is the vertical asymptote for the reciprocal of y=8x-4

Mathematics
1 answer:
rjkz [21]2 years ago
6 0

Answer:

The vertical asymptote for the reciprocal of y=8x-4 is \frac{1}{2}

Step-by-step explanation:

Given Equation : y = 8x-4

Reciprocal of given equation =\frac{1}{y}=\frac{1}{8x-4}

Now to find the vertical asymptote

\frac{1}{y}=\frac{1}{8x-4}

Equate denominator to 0

8x-4=0

8x=4

x=\frac{4}{8}

x=\frac{1}{2}

So, The vertical asymptote is\frac{1}{2}

Hence the vertical asymptote for the reciprocal of y=8x-4 is \frac{1}{2}

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Solve the simultaneous equation<br> 2x+4y=1<br> 3x+5y=7b
Lyrx [107]

Step-by-step explanation:

  • 3x+5y=7b equation 1
  • 2x+4y=1

2x=-4y+1

  • x=(-4y+1)/2
  • x=(-4y+1)/2 in equation 1

3×(-4y+1)/2+5y=7b

(-12y+3)/2+5y=7b

(-12y+3+10y)/2=7b

(-12y+3)/2=7b

-12y+3=14b

-12y=14b-3

  • y=3-14b/12
  • y=3-14b/12 in x=(-4y+1)/2

x=(-4×{3-14b/12}+1)/2

x=(-3+14b)/3+1/2

x=14b/3×1/2

  • x=7b/3
8 0
2 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

4 0
3 years ago
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Which ordered pair in the form (a, b) is a solution of this equation?
Evgen [1.6K]

3a - 4b = 21


check (-2 , -3)


3(-2) -4(-3) =21


-6 +12  = 21


6 does not = 21  so NO


check (0 , 7)


3(0) -4(7) =21


0-28=21


-28 does not equal 21  so NO


check (-3 , -2)


3(-3) -4(-2) =21


-9 +8  = 21


1 does not = 21  so NO


check (7 , 0)


3(7) -4(0) =21


21  = 21

Choice D

5 0
3 years ago
What is the value of (f -9)(5)?
Darina [25.2K]

Answer:

5f - 45

Step-by-step explanation:

(f-9)(5)

5f-9*5

5f-45

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I need help finding x please?
enot [183]

\large\mathfrak{{\pmb{\underline{\blue{To\:find}}{\blue{:}}}}}

The value of x.

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

\longrightarrow{\green{x\:=\: 25° }} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

We know that,

\sf\purple{Sum\:of\:angles\:on\:a\:straight\:line\:=\:180°}

➪ 125° + x + 30° = 180°

➪ x + 155° = 180°

➪ x = 180° - 155°

➪ x = 25°

Therefore, the value of x is 25°.

Now, the three angles of the triangle are 125°, 25° and 30°.

\large\mathfrak{{\pmb{\underline{\pink{To\:verify}}{\pink{:}}}}}

✒ 125° + 25° + 30° = 180°

✒ 180° = 180°

✒ L. H. S. = R. H. S.

\boxed{Hence\:verified.}

\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{ヅ}}}}}

3 0
3 years ago
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