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Brilliant_brown [7]
3 years ago
15

What is the vertical asymptote for the reciprocal of y=8x-4

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer:

The vertical asymptote for the reciprocal of y=8x-4 is \frac{1}{2}

Step-by-step explanation:

Given Equation : y = 8x-4

Reciprocal of given equation =\frac{1}{y}=\frac{1}{8x-4}

Now to find the vertical asymptote

\frac{1}{y}=\frac{1}{8x-4}

Equate denominator to 0

8x-4=0

8x=4

x=\frac{4}{8}

x=\frac{1}{2}

So, The vertical asymptote is\frac{1}{2}

Hence the vertical asymptote for the reciprocal of y=8x-4 is \frac{1}{2}

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Part 1) 30\ coupons

Part 2) 12\ sandwiches

Part 3) 60\ push-ups

Part 4) 96\ minutes

Part 5) \$95

Part 6) 1\frac{7}{8}\ cups\ of\ pretzel

Step-by-step explanation:

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Using proportion, find out the number of sandwiches

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\frac{1}{2.50}=\frac{x}{30}\\\\x=30/2.50\\\\x= 12\ sandwiches

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\frac{25}{60}\ \frac{miles}{minutes}=\frac{40}{x}\ \frac{miles}{minutes}\\\\x=60(40)/25\\\\x=96\ minutes

Part 5) we know that

For every bar of soap that Aly sells, she earns $5

For every mug that Janet sells, she earns twice as much as Aly

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Part 6) we know that

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Convert to mixed number

\frac{15}{8}=\frac{8}{8}+\frac{7}{8}=1\frac{7}{8}\ cups\ of\ pretzel

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