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2 years ago

Use the drawing tool(s) to form the correct answer on the provided graph.

Mathematics

1 answer:

AlekseyPX2 years ago

5 0

The solutions to the system of equations are (-2,-6) and (4,6)

<h3>How to determine the system of equations?</h3>

We have:

-2x + y = -2

$y = -\frac12x^2 + 3x + 2$

Next, we plot the graph of both functions.

From the attached graph, the equations intersect at (-2,-6) and (4,6)

Hence, the solutions to the system of equations are (-2,-6) and (4,6)

Read more about system of equations at:

brainly.com/question/21405634

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You ask 179 of your classmates how they feel about the school year being made longer. Complete the two-way frequency table to s

defon

Answer:

The answer are in the file

5 0

2 years ago

Please help with the first question....

Morgarella [4.7K]

Answer:

A) The functions are not inverses of each other.

Step-by-step explanation:

$f(g(x))=\sqrt{(x^2+3)-3}=\sqrt{x^2}=|x|\ne x$

The result of f(g(x)) is not always x, so the functions are not inverses of each other.

In general, a quadratic (or any even-degree polynomial) such as g(x) cannot have an inverse function because it does not pass the horizontal line test.

7 0

3 years ago

If the diameter of a circle is 6 inches, how long is the arc subtended by an angle measuring 70°?

yaroslaw [1]

Since the diameter of the circle is 6 inches, then the radius will be half that, or 3 inches,

$\bf \textit{arc's length}\\\\
s=\cfrac{r\pi \theta }{180} \quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=3\\
\theta =70
\end{cases}\implies s=\cfrac{3\cdot \pi \cdot 70}{180}\implies s=\cfrac{7\pi }{6}$

6 0

4 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

Read 2 more answers

How do you solve this ?

snow_tiger [21]

a and c are the anwsers to this it if you look at the back of the book it will give you anwsers

3 0

3 years ago