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3 years ago

Find the height of a triangle that has an area of 30 square units and a base measuring 12 units.

1 answer:

7 0

The equation for the area of a triangle is 1/2 x base x height. Plug in the values that you already have with h being the missing height value: 30= 1/2 x 12 x h Simplify: 30=6h Solve: 30/6=h 5=h The heoght of the triangle is 5 units

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2 years ago

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Lunna [17]

Answer:

b. the area to the right of 2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.

In this problem:

$X = 96, \mu = 72, \sigma = 12$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{96 - 72}{12}$

$Z = 2$

Percentage who did better:

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3 years ago

Find the missing side lengths. Leave your answers as radicals in simplest form. Show your work to support your answer

kotegsom [21]

Answer

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Step-by-step explanation:

$\sin( \alpha ) = \frac{2 \sqrt{2} }{x } \\ x = \frac{2 \sqrt{2} }{ \sin(45) } \\ x = 4 \\ {x}^{2} = {y}^{2} + 2 \sqrt{2} \\ {4}^{2} = {y}^{2} + (2 \sqrt{2 \: )}^{2} \\ 16 = {y}^{2} + 8 \\ 16 - 8 = {y}^{2} \\ y = \sqrt{8} \\ y = 2 \sqrt{2}$

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1 year ago