Answer:
I think it is 3.1
Step-by-step explanation:
make me brainlyest pls
Answer:
about 78 years
Step-by-step explanation:
Population
y =ab^t where a is the initial population and b is 1+the percent of increase
t is in years
y = 2000000(1+.04)^t
y = 2000000(1.04)^t
Food
y = a+bt where a is the initial population and b is constant increase
t is in years
b = .5 million = 500000
y = 4000000 +500000t
We need to set these equal and solve for t to determine when food shortage will occur
2000000(1.04)^t= 4000000 +500000t
Using graphing technology, (see attached graph The y axis is in millions of years), where these two lines intersect is the year where food shortages start.
t≈78 years
Answer:
29/18
Step-by-step explanation:
-11/6 + m = -2/9
Add 11/6 to both sides.
+11/6 -11/6 + m = -2/9 +11/6
m=29/18
I think it is C-two real solution
First we will find the derivative of each function and equate it to zero.
f` ( x ) = 6 x + 12
6 x + 12 = 0
6 x = - 12
x = - 2
f ( - 2 ) 0 12 - 24 + 16 = 4
f ( x ) min = 4
g` ( x ) = 4 cos ( 2 x - π )
4 cos ( 2 x - π ) = 0
cos ( 2 x - π ) = 0
2 x - π = 3π / 2
2 x = 5π /2
x = 5π/4
g ( 5π/4 ) = 2 sin ( 5π/2 - π ) + 4 = 2 ( sin 3π/2 ) + 4 = -2 + 4 = 2
g ( x ) min = 2 ( this is the smallest minimum value )
