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slamgirl [31]
2 years ago
14

Find the value of (1/2)^3 A. 1/6 B. 3/6 C. 1/8 D. 1/2​

Mathematics
2 answers:
Alex Ar [27]2 years ago
5 0

Answer:

I think it's letter C.

Step-by-step explanation:

not sure correct me if I'm wrong.

Llana [10]2 years ago
3 0

We are going to multiply the fraction 1/2, to the power of 3.

This means that:

  • 1 will be multiplied 3 times.
  • 2 will multiply 3 times

Therefore:

\bf{\left(\dfrac{1}{2}\right)^{3}=\dfrac{1\times1\times1}{2\times2\times2}=\dfrac{1}{8}     }

Therefore, the answer of the fraction (1/2)^3, is equal to 1/8.

  • The correct option is C.

\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}

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Test the four possible vertices that you found in the objective function in part A. Use those values to determine which set of v
irga5000 [103]

The testing of the four vertices of the objective function gives;

C(5, 0, 55) = 430

C(5, 30, 25) = 400

C(15, 30, 15) = 420

C(45, 0, 15) = 510 (maximum)

<h3>How to test objective functions?</h3>

The objective function is seen as attached.

Now, it is noticed that just two of the vertices are listed. The other two vertices are intersections of x + y + z = 60 with x = 5 and the constraints on y.

We will assume that; 0 ≤ y ≤ 30

Thus, the missing vertices are;

(x, y, z) = (5, 0, 55)  and  (5, 30, 25)

The two given vertices are;

(x, y, z) = (15, 30, 15)  and  (45, 0, 15)

Therefore, the objective function values are;

C(5, 0, 55) = 9·5 +6·0 +7·55 = 45 +0 +385 = 430

C(5, 30, 25) = 9·5 +6·30 +7·25 = 45 +180 +175 = 400

C(15, 30, 15) = 9·15 +6·30 +7·15 = 135 +180 +105 = 420

C(45, 0, 15) = 9·45 +6·0 +7·15 = 405 +0 +105 = 510

Read more about Objective Functions at; brainly.com/question/16826001

#SPJ1

5 0
1 year ago
The density of a certain material is such that it weighs 9 kilograms for every 7 cubic feet of volume. Express this density in p
Vadim26 [7]

Answer:

1.641× 10^-3 pounds/ cubic inch

Step-by-step explanation:

Density= mass / volume

Mass of the material= 9 kilograms

Volume= 7 cubic feet

Density= 9/7= 1.286 kg/ ft^3

Density= 1.286 kg/ ft^3

To Convert to pounds per inch

1 kg/ ft^3 = 0.00128 pound / cubic inch

1.286 kg/ ft^3 = X pounds/ cubic inch

X=( 1.286 × 0.00128)

= 0.0016407087 pounds/ cubic inch

= 1.641× 10^-3 pounds/ cubic inch

Hence,this density in pounds per inch is 1.641× 10^-3 pounds/ cubic inch

5 0
3 years ago
2. If m &lt;1 = 43, what is m &lt;4?
Alex17521 [72]
I do need help please
6 0
3 years ago
Which describes the amount of product the customers want to buy?
FromTheMoon [43]

Answer:

Demand

Step-by-step explanation:

Supply is what the stores have and demand is what the customers want

3 0
3 years ago
Read 2 more answers
-(b - 3) = -6(-2b - 7)
Georgia [21]

Answer:

b=-3

Step-by-step explanation:

8 0
3 years ago
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