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marta [7]
2 years ago
9

Which expression is equivalent to StartFraction 7 Superscript 5 Over 7 squared EndFraction?

Mathematics
1 answer:
stiks02 [169]2 years ago
5 0

The equivalent expression of \frac{7^5}{7^2} is \frac{7*7*7*7*7}{7*7}

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

\frac{7^5}{7^2}

Expand the numerator and the denominator

\frac{7^5}{7^2} = \frac{7*7*7*7*7}{7*7}

The above expression is represented by option (d)

Hence, the equivalent expression of \frac{7^5}{7^2} is \frac{7*7*7*7*7}{7*7}

Read more about equivalent expression at:

brainly.com/question/2972832

#SPJ1

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Answer:

Option B.

Step-by-step explanation:

The given vertices of triangle ABC are (-1, -1), (-1, -5) and (0.5, -5).

We need to find the coordinates of triangle when it is translated two units left.

So, the rule of translation is

(x,y)\rightarrow (x-2,y)

Using this rule, we get

A(-1,-1)\rightarrow A'(-1-2,-1)=A'(-3,-1)

B(-1,-5)\rightarrow B'(-1-2,-5)=B'(-3,-5)

C(0.5,-5)\rightarrow C'(0.5-2,-5)=C'(-1.5,-5)

The vertices of triangle A'B'C' are A'(-3,-1), B'(-3,-5) and C'(-1.5,-5).

Therefore, the correct option is B.

8 0
3 years ago
Read 2 more answers
Find the 74th term in the sequence: 83,79,75 show work
Maslowich

Answer:

a₇₄ = - 209

Step-by-step explanation:

There is a common difference between consecutive terms , that is

79 - 83 = 75 - 79 = - 4

This indicates the sequence is arithmetic with nth term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 83 and d = - 4 , then

a₇₄ = 83 + (73 × - 4) = 83 + (- 292) = 83 - 292 = - 209

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Select the statement that best justifies the conclusion based on the given information.
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Your Answer Is C. Distributive 
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\displaystyle 10q + 15n=49\quad \Big|-15n\\\\10q=49-15n\quad \Big|:10\\\\q= \frac{49-15n}{10}
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