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marta [7]
1 year ago
9

Which expression is equivalent to StartFraction 7 Superscript 5 Over 7 squared EndFraction?

Mathematics
1 answer:
stiks02 [169]1 year ago
5 0

The equivalent expression of \frac{7^5}{7^2} is \frac{7*7*7*7*7}{7*7}

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

\frac{7^5}{7^2}

Expand the numerator and the denominator

\frac{7^5}{7^2} = \frac{7*7*7*7*7}{7*7}

The above expression is represented by option (d)

Hence, the equivalent expression of \frac{7^5}{7^2} is \frac{7*7*7*7*7}{7*7}

Read more about equivalent expression at:

brainly.com/question/2972832

#SPJ1

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Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.
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Answer:

The solution of the given initial value problems in explicit form is y=x-x^2-2  and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

y'=1-2x

It can be written as

\frac{dy}{dx}=1-2x

Use variable separable method to solve this differential equation.

dy=(1-2x)dx

Integrate both the sides.

\int dy=\int (1-2x)dx

y=x-2(\frac{x^2}{2})+C                  [\because \int x^n=\frac{x^{n+1}}{n+1}]

y=x-x^2+C              ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

-2=1-(1)^2+C

-2=1-1+C

-2=C

The value of C is -2. Substitute C=-2 in equation (1).

y=x-x^2-2

Therefore the solution of the given initial value problems in explicit form is y=x-x^2-2 .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

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