Answer:
do you have a picture of the problem as well?
Step-by-step explanation:
The area of the circle will be equal to 11309.733 square centimetres.
<h3>What is an area?</h3>
The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.
The area of the circle will be calculated by the following formula:-
Area = πr²
Area = π x ( 60 x 60 )
Area = 3.14 x 60 x 60
Area = 11309.733 square centimeters.
Therefore the area of the circle will be equal to 11309.733 square centimetres.
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The answer is C) 160.
We know this because if mA = 50, we know that mC must also be 50. This is due to the fact that AB = BC. This leaves us with mB as 80 since the angles of a triangle always have to equal 180.
Now knowing this, it is easy to find the arc lengths in degrees. When you have a transcribed triangle, all we are going to do here is double the angle of the triangle to get the arc measure.
mB = 80
80*2 = 160
Answer: 44 miles
WORKINGS
Given,
The distance between Indianapolis and Lima, IL = 173 miles
The distance between Indianapolis and Dayton, ID = 165 miles
The distance between Dayton and Lima, DL is unknown
Since there are straight roads connecting the three cities, the connection between them form a right angles triangle.
The right angle is at Dayton
The hypotenuse is the distance between Indianapolis and Lima, IL
Therefore IL^2 = ID^2 + DL^2
173^2 = 165^2 + DL^2
DL^2 = 173^2 – 165^2
DL^2 = 29929 – 27225
DL^2 = 2704
DL = 52 miles
Therefore, The distance between Dayton and Lima, DL = 52 miles
The question is asking how many more miles would Meg drive if she stopped in Dayton first than if she drove directly to Lima.
That is, Distance of Indianapolis to Dayton + Distance of Dayton to Lima – Direct distance of Indianapolis to Lima
That is, ID + DL – IL
= 165 miles + 52 miles – 173 miles
= 217 miles – 173 miles
= 44 miles
Therefore, Meg would drive 44 more miles if she stopped in Dayton first than if she drove directly to Lima.