Answer:
Probability of choosing green and yellow treat is higher than Probability of choosing an orange and yellow treat by 0.08
Step-by-step explanation:
Given -
Green and yellow gummy treats = 20
Red and yellow gummy treats = 14
Orange and yellow gummy treats = 16
Total gummy treat = 20+14+16 = 50
Probability of choosing green and yellow treat = 20/50 = 0.4
Probability of choosing an orange and yellow treat = 16/50 = 0.32
Probability of choosing green and yellow treat is higher than Probability of choosing an orange and yellow treat by 0.08
Answer:
A) 29
Step-by-step explanation:
DG = GJ
GJ = DG = 4x + 17
DJ = DG + GJ
11x + 25 = 4x + 17 + 4x + 17
11x + 25 = 4x + 4x + 17 + 17 {Combine like terms}
11x + 25 = 8x + 34
Subtract 25 from both sides
11x = 8x + 34 - 25
11x = 8x + 9
Subtract 8x from both sides
11x - 8x = 9
3x = 9
Divide both sides by 3
x = 9/3
x = 3
DG = 4x + 17
= 4*3 + 17
= 12 + 17
DG = 29
Answer:
Step-by-step explanation:
Giving:
<u>Swimming</u>
![P(Win[Swim])= 65\%](https://tex.z-dn.net/?f=P%28Win%5BSwim%5D%29%3D%2065%5C%25)
<u>Running</u>
![P(Win[Run])= 85\%](https://tex.z-dn.net/?f=P%28Win%5BRun%5D%29%3D%2085%5C%25)
<u>Required</u>
Determine the probability of winning at running and losing at swimming
First, we calculate the probability of losing at swimming using
Substitute 65% for P(Win)
![65\% + P(Lose[Swim]) = 1](https://tex.z-dn.net/?f=65%5C%25%20%2B%20P%28Lose%5BSwim%5D%29%20%3D%201)
Collect Like Terms
![P(Lose[Swim]) = 1 - 65\%](https://tex.z-dn.net/?f=P%28Lose%5BSwim%5D%29%20%3D%201%20-%2065%5C%25)
![P(Lose[Swim]) = 35\%](https://tex.z-dn.net/?f=P%28Lose%5BSwim%5D%29%20%3D%2035%5C%25)
The required probability is then calculated using:
![Probability = P(Win[Run]) * P(Lose[Swim])](https://tex.z-dn.net/?f=Probability%20%3D%20P%28Win%5BRun%5D%29%20%2A%20P%28Lose%5BSwim%5D%29)
Convert to decimal
Answer:
92
Step-by-step explanation:
1
44
48+
92
