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solong [7]
3 years ago
6

An IV fluid contains 75 mg of Drug B in 500 ml of the IV fluid. If the patient needs 300 mg of this medication, how much of this

IV fluid should be infused
Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

2000ml = 2L of this IV fluid should be infused.

Step-by-step explanation:

This problem can be solved by a simple rule of three, in which the relationship between the measures is direct, which means that there is a cross multiplication.

The problem states that each 75 mg of the medication contains 500 ml of IV fluid. How many ml of IV fluid are there in 300 mg of the medication?

So

75mg - 500ml

300 mg - x ml

75x = 300*500

x = \frac{300*500}{75}

x = 4*500

x = 2000ml

2000ml = 2L of this IV fluid should be infused.

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kupik [55]
Find a_{1} by plugging in 1 into n:
a_{1} = 98-2(1)=96

Find a_{11 by plugging in 11 into n:
a_{11} = 98-2(11)
a_{1} =98-22=76

Now to find the sum your formula is:
S_{n} = \frac{n}{2} ( a_{1} + a_{n})
n = 11,   a_{1} = 96 ,  a_{11} =76

Now plug that into the formula
S_{11} = \frac{11}{2} (96+76)
S_{11} = 5.5(172)=946

Hope that helps
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3 years ago
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Step-by-step explanation:

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3 years ago
Find the common difference for an arithmetic series with <br> a1=5 and S10 = 320.
maw [93]

Answer:

6

Step-by-step explanation:

Let n = a_{10}. We know the formula for the sum of an arithmetic sequence is:

S_{n} = \frac{n(a_{1}+a_{n} )}{2}

Where n is the number term you are finding the sum up to, a1 is the first term, and an is the nth term. We can substitute what we have:

320=\frac{10(5 + n)}{2}

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The formula to find the nth term of an arithmetic series is:

a_{n} = a_{1} + (n-1)d

Where d is the common difference. Again, we can plug in what we have;

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