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solong [7]
3 years ago
6

An IV fluid contains 75 mg of Drug B in 500 ml of the IV fluid. If the patient needs 300 mg of this medication, how much of this

IV fluid should be infused
Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

2000ml = 2L of this IV fluid should be infused.

Step-by-step explanation:

This problem can be solved by a simple rule of three, in which the relationship between the measures is direct, which means that there is a cross multiplication.

The problem states that each 75 mg of the medication contains 500 ml of IV fluid. How many ml of IV fluid are there in 300 mg of the medication?

So

75mg - 500ml

300 mg - x ml

75x = 300*500

x = \frac{300*500}{75}

x = 4*500

x = 2000ml

2000ml = 2L of this IV fluid should be infused.

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Find five consecutive integers such that: "the sum of the first and 4 times the third is equal to 60 less than 3 times the sum o
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Consecutive integers are integers that come one after another in order. For example, 2, 3, and 4 are all consecutive integers, as well as 100, 101, and 102. In general, if we have some integer n, the consecutive integers following it will be n + 1, n + 2, n + 3, etc. Here, we have five. If we

  • Call the first integer n,
  • Then the second integer will be n + 1,
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Now, let's break down the equation in English. We'll use #1, #2, #3, #4, and #5 as stand-ins for the five integers just so we can get things set up, then we'll replace them with the expressions we came up with in the first part. Starting from the beginning of the statement, let's translate words to symbols:

  • "The sum of the first and 4 times the third" → #1 + 4 × #3
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Putting that all together, we get the equation

#1 + 4 × #3 = 3 × (#2 + #4 + #5) - 60.

Replacing our stand-ins for the expressions we came up with, it becomes

n + 4(n + 2) = 3[(n + 1) + (n + 3) + (n + 4)] - 60

We can now start to simplify our equation to find n (the first integer) and the rest will follow easily from that. I'll start by focusing on the left side. We can distribute and combine like terms like so:

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Dealing with the right, we can get rid of some redundant parentheses and carry out the same process:

3[(n + 1) + (n + 3) + (n + 4)] - 60 = 3(n + 1 + n + 3 + n + 4) - 60

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Our simplified equation now becomes

5n + 8 = 9n - 36.

Subtracting 5n from either side:

8 = 4n - 36

Adding 36 to either side:

44 = 4n

And dividing either side by 4:

11 = n.

We now know that our first integer is 11, which means that our 5 consecutive integers are 11, 12, 13, 14, and 15.

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