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Virty [35]
2 years ago
14

TRUE OR FALSE

Mathematics
1 answer:
DochEvi [55]2 years ago
3 0

Answer:

True

Step-by-step explanation:

Cant really provide step by step per se.

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weeeeeb [17]
Approximately equal to symbol
And it’s mostly used in terms of numerical approximations
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There is $100 it goes up 10% how much is it
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Its 110 cuz it goes up 10% if it was 20% it would be 120
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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
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Real answers and explanations ONLY! I’ll name you brainiest if correct
Juli2301 [7.4K]

Answer:

  • 1/10⁶ or 0.000001

Step-by-step explanation:

<u>For every time you have a probability of getting 1 is:</u>

  • P(1) = 1/10

<u>For all 6, the probability of outcome of 1 is:</u>

  • P(1x6) = (1/10)⁶ = 0.000001
8 0
2 years ago
A right triangle has a leg of 11 and a hypotenuse of 16. Find the missing leg (in simplest radical form)
igomit [66]

Answer:

11^2 + b^2 = 16^2

121 + b^2  = 256

b^2 = 135

b = 3 X q(15)

Step-by-step explanation:

8 0
3 years ago
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