WILL GIVE BRAINLIEST, PLEASE HELP
2 answers:
Hey. Let me help you on this one.
In order for us to solve this question, we need to know how these variables work within the problem. There are many ways of solving this problem; however, we will solve this logically by using both order of operations, and simplification of the problem.
Let's look at the first one.
can be simplified and made into (15)x. We got this expression by adding 12 and 3.
Now, let's review the second one
can be simplified into (15x)x, and the latter one can be simplified by multiplying two unknowns together to make 15x^2 (it is squared since we have multiplied two exact numbers together)
The second one is not similar to the first one, and we need at least three to know which one of them is not equivalent to the rest.
The third expression is, which is a simplified version of the first one. This shows us that the second statement is not similar to the rest.
Fourth one is, and it can be simplified by adding 12x and 3x together, giving us 15x. This one is similar to other two expressions.
After simplifying each and other one, we now know which one is not equivalent to others - second option.
Answer: is not equivalent to other expressions.
In order for us to solve this question, we need to know how these variables work within the problem. There are many ways of solving this problem; however, we will solve this logically by using both order of operations, and simplification of the problem.
Let's look at the first one.
Now, let's review the second one
The second one is not similar to the first one, and we need at least three to know which one of them is not equivalent to the rest.
The third expression is
Fourth one is
After simplifying each and other one, we now know which one is not equivalent to others - second option
Answer:
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Answer:
a) Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
b) If the true mean is 190 days, Type II error can be made.
Step-by-step explanation:
Let mu be the mean life of the batteries of the company when it is used in a wireless mouse
Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.
That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.
Answer: C. Yes, because -2.77 falls in the critical region .
Step-by-step explanation:
Let be the population mean .
As per given , we have
Since the alternative hypothesis is left-tailed and population standard deviation is not given , so we need to perform a left-tailed t-test.
Test statistic :
Also, it is given that ,
n= 48
s= 10
Degree of freedom = df = n-1= 47
Using t-distribution , we have
Critical value =
Since, the absolute t-value (|-2.77|=2.77) is greater than the critical value.
So , we reject the null hypothesis.
i.e. -2.77 falls in the critical region.
[Critical region is the region of values that associates with the rejection of the null hypothesis at a given probability level.]
Conclusion : We have sufficient evidence to support the claim that these inspectors are slower than average.
Hence, the correct answer is C. Yes, because -2.77 falls in the critical region