All categories

1 year ago

Evaluate the expression below. 15 ÷ (5 - 2) + 4 =

Mathematics

1 answer:

lana [24]1 year ago

3 0

Answer:

Step-by-step explanation:

This is an order of operations question. First in PEMDOS you want to do your parenthesis, turn (5-2) into 3,

15 ÷ 3 + 4

Then do your divison, turning 15 ÷ 3 into 5

5 + 4

Then finish with 5 + 4

The answer is 9

You might be interested in

Simplify the expression b+2/b^2-4

Lubov Fominskaja [6]

3b because b^2-4= 1/b. So 2/1/b= 2b b+2b = 3b

8 0

2 years ago

Read 2 more answers

A log is 20 m long, correct to the nearest metre.

Marat540 [252]

Answer:

222 fence posts

Step-by-step explanation:

Since the log is 20 m long, correct to the nearest metre and has to be cut into fence posts which must be 90 cm long, correct to the nearest 10 centimetres, there can be x fence posts 90 cm long.

So, we have x × 90 cm = 20 m

x × 0.9 m = 20 m

x = 20 m/0.9 m

x = 222.22

x ≅ 222 fence posts

So, the largest number of fence posts that can possibly be cut from the log is 222 fence posts.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%20%5Cred%7B%5Cfrak%7B%20Question%7D%7D" id="TexFormula1" title=" \large \red{\frak

lbvjy [14]

Answer:

$\sf \: \fbox{Option C) \: The salary of B is 6000₹}$

Step-by-step explanation:

Let the salary or A is x and salary of B is y.

now,

Condition one,The sum of 3/4th of A’s salary and 5/3rd of B’s salary is ₹16,000.

writing above statement in equation form,

$\sf \frac{3x}{4} + \frac{5y}{3} = 16000$

Multiplying above equation with twelve,

$\sf \frac{3x}{4} + \frac{5y}{3} = 16000 \\ \sf \frac{12 \times 3x}{4} + \frac{12 \times 5y}{3} = 16000 \times 12 \\ \sf \fbox{9x + 20y = 192000} \rightarrow eq. 1$

and condition two,

The difference of their salaries is ₹2000

$\sf \: x - y = 2000$

Multiplying above equation with 20

$\sf \fbox{\: 20x -20y = 40000} \rightarrow eq.2$

On adding equation 1 and equation 2,

$\sf9x + \cancel{20y} = 192000 \\ \sf 20x - \cancel{20y} = 40000 \\ \hline \sf 29x + 0y = 232000 \\ \sf x = \frac{232000}{29} \\ \sf \: \fbox{x = 8000₹}$