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dybincka [34]
3 years ago
11

2. Determine if either of the following equations are functions? Draw the graphs and explain how

Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

Both equation represent functions

Step-by-step explanation:

The function is the relation that for each input, there is only one output.

A. Consider the equation

y=-\dfrac{3}{5}x+2

This equation represents the function, because for each input value x, there is exactly one output value y.

To check whether the equation represents a function, you can use vertical line test. If all vertical lines intersect the graph of the function in one point, then the equation represents the function.

When you intersect the graph of the function y=-\dfrac{3}{5}x+2 with vertical lines, there will be only one point of intersection (see blue graph in attached diagram). So this equation represents the function.

B. Consider the equation

y=x-x^2

This equation represents the function, because for each input value x, there is exactly one output value y.

When you intersect the graph of the function y=x-x^2 with vertical lines, there will be only one point of intersection (see green graph in attached diagram). So this equation represents the function.

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Answer:

The vertex would be (-3, -1)

Step-by-step explanation:

Since this is in vertex form already, a(x-h)^2+k  where h is the x value of the vetex, and k is y.

We would take the opposite of +3 and get -3, which gives us our x cordinate.

We don't change the k value, so it just stays -1, giving us our y value.

Therefore, the vertex is at (-3, -1)

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2 years ago
The top and bottom margins of a poster are 8 cm and the side margins are each 6 cm. If the area of printed material on the poste
hammer [34]

Answer:

Dimensions of the poster

Width  29.10 cm

Height 38.80 cm

A(min) = 1129.08 cm²

Step-by-step explanation:

Printed area = 390 cm² = Ap

Lets call x and y dimensions of printed area

x   width

y   height

Then Ap = x*y    and

y = Ap/x    ⇒    y = 390/x

Then   total area of the poster is:

A(t)  = ( x  + 12 ) * ( y + 16 )         and   y = 390/x

A as a function of x

A(x) = ( x  + 12 ) * ( 390/x + 16 )   ⇒  A(x) = 390 + 16x + 4680/x + 192

A(x) = 582 + 16x + 4680/x     (1)

Taking derivatives

A´(x) =  16 - (4680/x²)         ⇒ A´(x)  =  0

[ 16x² -4680] /x² = 0     16x²- 4680 = 0    ⇒     x² = 4680/16

x = 17.10 cm        and    y = 390/x      y = 390/17.10      y = 22.80 cm

A(t) = ( 17.10 + 12 ) * ( 22.80 + 16 )

A(t) = 29.10 * 38.80

A(t) = 1129.08 cm²

If we substitute  in equation (1) the value of x  ( 17.10) we see A(x) > 0

Then there is a minimun at the point x = 17.10

4 0
4 years ago
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Answer:

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