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kompoz [17]
2 years ago
9

What is the product of (6x^2 − 8)(9x^2 – x + 1)?

Mathematics
1 answer:
creativ13 [48]2 years ago
8 0

(6 {x}^{2}  - 8)(9 {x}^{2}  - x + 1) \\ 54 {x}^{4}      -  6 {x}^{3}   + 6 {x}^{2}  - 72{x}^{2}  + 8x - 8 \\ 54 {x}^{4}  - 6 {x}^{3}  - 66 {x}^{2}  + 8x - 8

Hope it helps

please give brainliest

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Polygon F has an area of 36 square units. Aimar drew a scaled version of Polygon F and labeled it Polygon G. Polygon G has an ar
Free_Kalibri [48]

Answer:

1/3

Step-by-step explanation:

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

Each side of Polygon FFF was multiplied by a certain value, known as the scale factor , to result in an area that is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

[Show me an example of how scale factor affects area]

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction

 

 

\begin{aligned} A &= \left(l\times\dfrac1{10}\right)\times\left(w\times\dfrac1{10}\right) \\ \\ A&= l\times w\times\dfrac1{10}\times\dfrac1{10} \\ \\ A&= lw \times \left(\dfrac1{10}\right)^2\end{aligned}  

 

 

 

 

 

 

 

 

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction\left(\dfrac1{10}\right)^2  

 

left parenthesis, start fraction, 1, divided by, 10, end fraction, right parenthesis, start superscript, 2, end superscript

Hint #22 / 3

The area of a polygon created with a scale factor of \dfrac1x  

x

1

​  start fraction, 1, divided by, x, end fraction has \left(\dfrac1{x}\right)^2(  

x

1

​  )  

2

left parenthesis, start fraction, 1, divided by, x, end fraction, right parenthesis, start superscript, 2, end superscript the area of the original polygon:

\left(\text{scale factor}\right)^2=\text{fraction of the area the scale copy has}(scale factor)  

2

=fraction of the area the scale copy hasleft parenthesis, s, c, a, l, e, space, f, a, c, t, o, r, right parenthesis, start superscript, 2, end superscript, equals, f, r, a, c, t, i, o, n, space, o, f, space, t, h, e, space, a, r, e, a, space, t, h, e, space, s, c, a, l, e, space, c, o, p, y, space, h, a, s

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF. Let's substitute \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction into the equation to find the scale factor.

\left(\dfrac1{?}\right)^2=\dfrac19(  

?

1

​  )  

2

=  

9

1

​  left parenthesis, start fraction, 1, divided by, question mark, end fraction, right parenthesis, start superscript, 2, end superscript, equals, start fraction, 1, divided by, 9, end fraction

The scale factor is \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction.

Hint #33 / 3

Aimar used a scale factor of \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction to go from Polygon FFF to Polygon GGG.

4 0
3 years ago
Read 2 more answers
Rezolvati in multimea numerelor intregi ecuatiile:3(19-x)=4x-13
Hitman42 [59]
What language is this in because I don't understand any of it?
6 0
3 years ago
A sphere has a diameter of 14.5 inches.
dlinn [17]

Answer:

≈ 660.5 in²

Step-by-step explanation:

The surface area (A) of a sphere is calculated using the formula

A = 4πr² ← r is the radius

Given diameter = 14. 5 then radius = 7.25, thus

A = 4π × 7.25² = 4π × 52.5625 ≈ 660.5 in²

4 0
3 years ago
Is 1/8 equal to 8? If not what is it?
son4ous [18]
It is not equal to 8 but it is the reciprocal of it.
5 0
3 years ago
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I need help starting the question
Nadya [2.5K]
What do you mean? its a question, but you asked how to start a question???
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7 0
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