In a motor, the RATIO of output work to input work, expressed as a percentage, is the efficiency of the motor.
Answer : Ratio
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Answer:
H₂
Explanation:
To solve this question we must find, as first, find the molar mass of the homonuclear diatomic gas using Graham's law. With the molar mass we can identify this gas
<em>Graham's law:</em>

<em>Where V is the speed of the gases and m the molar mass of those:</em>
<em>As Va is 3.98 times Vb (And mB is molar mass of oxygen gas = 32g/mol)</em>

15.84 = 32g/mol / mA
mA = 2.02g/mol
As is a homonuclear diatomic gas, the molar mass of the atom is 1.01g/mol. Thus, the gas is:
<h3>H₂</h3>
Abhishek Singh present invention to provide
Answer:
A sample of pure NO2 is heated to 338 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+O2(g) At equilibrium the density of the gas mixture is 0.515 g/L at 0.745 atm .
(4x^2)x
Kc= -----------
(A-2x)^2
PV=nRT
n/v = P/RT = .745/(0.0821)(334+273) = .01495
To Find the initial molarity of NO2
(mol/L)(g/mol) + (mol/L)(g/mol) + (mol/L)(g/mol)= g/L
Thus:
46(A-2x) + 2x(30) + 32x = .515 g/L
46A-92x+60x+32x = .515
46A=.515
A=.01120 M
Using the total molarity found
(A-2x)+2x+x = .01495 M
A+x=.01495
Plug in A found into the above equation:
.01120+x = .01495
x=.00375
Now Plug A and x into the original Equilibrium Constant Expression:
(4x^2)x
Kc= -----------
(A-2x)^2
Kc = 0.000014
Explanation: