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guapka [62]
2 years ago
15

1. list at least two possible sources of error from the experiment. would these errors result in an overestimation or an underes

timation of the concentration of acetic acid in the vinegar
Chemistry
1 answer:
quester [9]2 years ago
6 0

An error in estimation could arise owing to;

1) Inaccurate measurement of the volumes of the solutions

2) When the reaction vessels are not properly cleaned

<h3>What is error in an experiment?</h3>

Error could occur in an experiment when values are misread. The error could be  random error or a systematic error.

The major ways in which an error can occur in the estimation of concentration of acetic acid in the vinegar are;

1) Inaccurate measurement of the volumes of the solutions

2) When the reaction vessels are not properly cleaned

Learn more about errors in experiment:brainly.com/question/14149934

#SPJ1

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In a motor, the_____of output work to input work,expressed as a percentage, is the efficiency of the motor.
BartSMP [9]

In a motor, the RATIO of output work to input work, expressed as a percentage, is the efficiency of the motor.

Answer : Ratio

8 0
3 years ago
Which step of the scientific method involves making an inference?
maria [59]

The only logical answer would be to D) draw a conclusion, given that an inference is another word for conclude. Helpful tip, if you are dealing with the scientific method just google the method and boom! there is your answer.


6 0
3 years ago
Read 2 more answers
State of matter
Nina [5.8K]

Answer:

H₂

Explanation:

To solve this question we must find, as first, find the molar mass of the homonuclear diatomic gas using Graham's law. With the molar mass we can identify this gas

<em>Graham's law:</em>

\frac{V_a}{V_b} =\sqrt{\frac{m_B}{m_A} }

<em>Where V is the speed of the gases and m the molar mass of those:</em>

<em>As Va is 3.98 times Vb (And mB is molar mass of oxygen gas = 32g/mol)</em>

3.98 =\sqrt{\frac{32g/mol}{m_A} }

15.84 = 32g/mol / mA

mA = 2.02g/mol

As is a homonuclear diatomic gas, the molar mass of the atom is 1.01g/mol. Thus, the gas is:

<h3>H₂</h3>
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3 years ago
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3 years ago
A sample of pure NO2 is heated to 338 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+
natima [27]

Answer:

A sample of pure NO2 is heated to 338 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+O2(g) At equilibrium the density of the gas mixture is 0.515 g/L at 0.745 atm .

(4x^2)x

Kc= -----------

(A-2x)^2

PV=nRT

n/v = P/RT = .745/(0.0821)(334+273) = .01495

To Find the initial molarity of NO2

(mol/L)(g/mol) + (mol/L)(g/mol) + (mol/L)(g/mol)= g/L

Thus:

46(A-2x) + 2x(30) + 32x = .515 g/L

46A-92x+60x+32x = .515

46A=.515

A=.01120 M

Using the total molarity found

(A-2x)+2x+x = .01495 M

A+x=.01495

Plug in A found into the above equation:

.01120+x = .01495

x=.00375

Now Plug A and x into the original Equilibrium Constant Expression:

(4x^2)x

Kc= -----------

(A-2x)^2

Kc = 0.000014

Explanation:

3 0
3 years ago
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