C) is higher for nonpolar substances than for polar ones
Answer:
The answer to your question is: 55.84 u. The element is Iron
Explanation:
isotope 1 mass 53.94 u abundance 5.85%
2 mass 55.9349 abundance 91.75%
3 mass 56.9354 abundance 2.12%
4 mass 57.9333 abundance 0.28%
average atomic mass = (53.94 x 0.0585) + (55.9349 x 0.9175) + (56.9354 x 0.0212) + (57.9333 x 0.0028)
average atomic mass = 3.155 + 51.32 + 1.207 + 0.1622
average atomic mass = 55.84 u. The element is Iron
Answer:
pH of the solution is 10.37
Explanation:
![pOH=pkb+log\frac{[salt]}{[base]}](https://tex.z-dn.net/?f=pOH%3Dpkb%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bbase%5D%7D)
kb = 
pkb = -log kb
= 
= 3.35
salt is methylammonium bromide and methylamine is base
Substitute the values in the above expression as follows:
![pOH=pkb+log\frac{[salt]}{[base]} \\=3.35+log\frac{0.35}{0.18} \\=3.35+0.28\\=3.63](https://tex.z-dn.net/?f=pOH%3Dpkb%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bbase%5D%7D%20%5C%5C%3D3.35%2Blog%5Cfrac%7B0.35%7D%7B0.18%7D%20%5C%5C%3D3.35%2B0.28%5C%5C%3D3.63)
pH = 14 - pOH
= 14 - 3.63
= 10.37
pH of the solution is 10.37