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2 years ago

Can y’all help me out please

Mathematics

2 answers:

anygoal [31]2 years ago

7 0

Answer:

may or may not be

Explanation:

Because we only know two sides, A-center and C-center, we cannot verify that ABCD is a parallelogram. Corner D could be 40 units away from the center, and Corner B might be 12 units away. If you imagine pulling back the corners (away from the center), the length between two corners can be equal even if the shape is not parallel.

For example, BC could have a length of 10, and AD could have a length of 15. These sides could be at completely different angles/slants (so they might not be parallel), and still maintain a middle measurement of 4.0 on both sides.

However, all sides could be parallel, but we are not provided enough information to confirm this possibility.

natta225 [31]2 years ago

4 0

Answer: C
ABCD may or may not be a parellolgram. Line BD bisects line AC, however we cant figure out if line AC bisects line BD.

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dolphi86 [110]

Answer:

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Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

First case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

Second case

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

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Calculate the answer to the correct number of significant digits. (91.01)(10.7)

aalyn [17]

Answer:

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Step-by-step explanation:

(91.01)*(10.7)

91.01*(10.7)

91.01*10.7

973.80700

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