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Brut [27]
3 years ago
6

The height (h) in feet of a baseball on Earth after t seconds can be modeled by the function h(t) = -16(t – 1.5)2 + 36, where -1

6 is a constant in ft/s2 due to Earth's gravity. The gravity on Mars is only 0.4 times that on Earth. If the same baseball were thrown on Mars, it would reach its maximum height 59 feet higher and 2.5 seconds later than it did on Earth. Write a height function for the baseball thrown on Mars.
A) y = -0.4(t – 4)2 + 95
B) y = -0.4(t – 2.5)2 + 59
C) y = -6.4(t – 4)2 + 95
D) y = -6.4(t – 2.5)2 + 59
Mathematics
1 answer:
marishachu [46]3 years ago
3 0
Y = (-16*0.4)(t - 2.5-1.5)^2 + 36 + 59
y = 6.4(t - 4)^2 + 95
 
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The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

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26. 60 degrees vertical to angle DCE.

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