The horizontal distance from the helicopter to the landing pad is 1658.81 feet
<em><u>Solution:</u></em>
The figure is attached below
Triangle ABC is a rightangled triangle
A helicopter is flying at point A and landing pad is at point c
Angle of depression of the helicopter is 37 degrees so angle of elevation of this helicopter from landing pad will be same as 37 degrees
The helicopter is 1250 feet from the ground
Therefore, AB = 1250 feet
To find: horizontal distance from the helicopter to the landing pad
BC is the horizontal distance from the helicopter to the landing pad
BC = ?
By the definition of tan,
Thus the horizontal distance from the helicopter to the landing pad is 1658.81 feet
The area of the shape is 180 square feet if the length of the diagonals are 20 and 18 ft respectively, option (a) is correct.
<h3>What is quadrilateral?</h3>
It is defined as the four-sided polygon in geometry having four edges and four corners. Two pairs of congruent sides, and it has one pair of opposite congruent angles.
We know the area of the kite = pq/2
Where p and q are the length of the diagonals
p = 10+10 = 20 ft
q = 7+11 = 18 ft
Area = (20×18)/2
Area = 180 square feet
Thus, the area of the shape is 180 square feet if the length of the diagonals are 20 and 18 ft respectively option (a) is correct.
Learn more about the quadrilateral here:
brainly.com/question/6321910
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It drops 32 feet each second so at six seconds it will have dropped 176 feet
Thank you for posting your question here. I think the question is "
<span>What is the estimated mean for the population? Explain your answer and show your work."
Below is the solution. I hope it helps.
</span>µ= (1*248 +2*567 +3*1402 +4*728 +5*419 +6*456 +7*203)/(1 +2 +3 +4 +5 +6 +7)
<span>=14752/28≈ 526.9</span>
Answer:
2.75
Step-by-step explanation:
1/4 x 11 = 2.75
