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Alik [6]
3 years ago
12

4x^5/2x^2+5=59 please help ​

Mathematics
1 answer:
meriva3 years ago
6 0

Answer:

{ \tt{ \frac{4 {x}^{5} }{2 {x}^{2} + 5 } = 59 }}

Cross multiply the variables:

{ \tt{4 {x}^{5}  = 59(2 {x}^{2}  + 5)}} \\ { \tt{4 {x}^{5}  = 118 {x}^{2}  + 295}} \\ { \tt{4 {x}^{5}  - 118 {x}^{2}  = 295}}

Factorise the equation:

{ \tt{ {x}^{2}(4 {x}^{3}  - 118) = 295 }}

Either x² or ( 4x³ - 118 ) is equal to 295:

For x²:

{ \tt{ {x}^{2}  = 295}} \\ { \tt{first \: answer : \: x =17.2  }}

For ( 4x³ - 118 ):

{ \tt{4 {x}^{3} = 413 }} \\ { \tt{ {x}^{3}  = 103.25}} \\ { \tt{second \: answer : \: x = 4.7 }}

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