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3 years ago

4x^5/2x^2+5=59 please help

Mathematics

1 answer:

meriva3 years ago

6 0

Answer:

${ \tt{ \frac{4 {x}^{5} }{2 {x}^{2} + 5 } = 59 }}$

Cross multiply the variables:

${ \tt{4 {x}^{5} = 59(2 {x}^{2} + 5)}} \\ { \tt{4 {x}^{5} = 118 {x}^{2} + 295}} \\ { \tt{4 {x}^{5} - 118 {x}^{2} = 295}}$

Factorise the equation:

${ \tt{ {x}^{2}(4 {x}^{3} - 118) = 295 }}$

Either x² or ( 4x³ - 118 ) is equal to 295:

For x²:

${ \tt{ {x}^{2} = 295}} \\ { \tt{first \: answer : \: x =17.2 }}$

For ( 4x³ - 118 ):

${ \tt{4 {x}^{3} = 413 }} \\ { \tt{ {x}^{3} = 103.25}} \\ { \tt{second \: answer : \: x = 4.7 }}$

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3 years ago

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shusha [124]

Answer:

Part A) The probability is closer to 0, because is less than 50%

Part B) The probability is closer to 1, because is greater than 50%

Step-by-step explanation:

we know that

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The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

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Part A) Is the probability of hitting the black circle inside the target closer to 0 or 1?

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Convert to percentage

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The probability is closer to 0, because is less than 50%

Part B) Is the probability of hitting the white portion of the target closer to 0 or 1?

In this problem we have

x------> is the area of the white portion of the target

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4x^5/2x^2+5=59 please help ​

4x^5/2x^2+5=59 please help