We need a system of equations here, one equation based on the NUMBER of tickets sold and another based on the MONEY earned by the sales. We have 2 different types of tickets: full price (f) and discount (d). The total number of tickets sold is 428; therefore, the first equation is f + d = 428. That accounts for the number of tickets sold. Each full price is 10.25 which can be represented as 10.25f, and each discount ticket costs 8 which can be represented as 8d. The money earned by selling these tickets at those prices was 3946. That means that the second equation is 10.25f + 8d = 3946. We will solve the first bolded equation for f to get f = 428 - d. Sub that value in for f in the second bolded equation: 10.25(428-d) + 8d = 3946. Distribute to get 4387 - 10.25d + 8d = 3946. Combine like terms to get -2.25d = -441. Solving for d we get 196. That means that there were 196 discounted tickets sold. Put that in for d in the first bolded equation to find the number of full price tickets. f + 196 = 428, and f = 232. There were 232 full price tickets sold. There you go!
Answer:
B. 1/m¹⁸
Step-by-step explanation:
To simplify the equation, we start with the values inside the brackets.
Therefore m⁻¹m⁵ results to m⁴.
This is because the sign between the m⁻¹ and m⁵ is multiplication, and when multiplying figures that have a similar base, we add the indices.
that is, -1+5=4
then we divide m⁴ by m⁻², that is, m⁴/m⁻²=m⁶
To divide figures that have the same base we subtract the powers.
That is, 4-(-2)=6
the resulting expression from inside the brackets will be (m⁶)³ which results to m⁻¹⁸ which is the same as 1/m¹⁸
Answer:
1 one answer, 2 lot of answers, 3 no answer
Step-by-step explanation:
I have to go to bed sorry
Answer:
Well, it depends on their heights . If both figures have same height, then the one with greater surface area will have greater volume.
Step-by-step explanation:
The first one I've already naswered: If two lines don't intersect, then they don't share a common point.
The second one:
If A is not the initial point, then AB is not a ray.
