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MissTica
3 years ago
11

According to the American Bureau of Labor Statistics, you will devote 37 years to sleeping and watching TV. The number of years

sleeping will exceed the number of years watching TV by 19. Over your lifetime, how many years will you spend on each of these activities?
Mathematics
1 answer:
Elanso [62]3 years ago
5 0

Answer:

Sleeping = 28 hrs

Watching TV = 9 hrs

Step-by-step explanation:

1) You know you will spend 37 years doing both things:

  • Sleeping + Watching.TV=37

2) You also know that you will spend 19 years more sleeping than watching TV:

  • Sleeping = 19+Watching.TV

3) Substitute your second equation in your first equation:

  • 19+Watching.TV+Watching.TV=37\\19+2*Watching.TV=37\\Watching.TV = \frac{37-19}{2} \\Watching.TV = 9 [years]

4) Substitute the result in your second equation:

  • Sleeping=19+9\\Sleeping = 28[years]
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The material point moves in a straight line according to the law s (t) = t ^ 2 + 10t - 5, the stage of the point's velocity at t
nikitadnepr [17]

Answer:

I think the answer is 19

Step-by-step explanation:

5 0
3 years ago
The odds of winning a goldfish toss game are 1:49. The probability of winning a claw game is 30%. Which game gives you a better
olga_2 [115]

Answer:

the claw game would give you a better %

Step-by-step explanation

when turned into a percent 1:49 becomes 2.040816326531% compared to the claw game that would give you a 30% chance of wining

6 0
3 years ago
I need help pls ASAP show your work
REY [17]

Answer:

X= 43/3

Step-by-step explanation:

-1/4 x 5 = 3/4x - 12

-5/4=3/4x -12

-5=3x - 48

-3x-5 = -48

-3x = -48 + 5

-3x= -43

-3 x= -43

X= 43/3

8 0
2 years ago
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4 0
3 years ago
Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest
s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and \varepsilon>0, we want to find a \delta such that |f(x)-14|

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that |x-5|. Then

|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta.

Then, if |x-5|, then |f(x)-14|. So, in this case, if 3\delta \leq \varepsilon we get that |f(x)-14|. The maximum value of delta is \frac{\varepsilon}{3}.

By definition, this procedure proves that \lim_{x\to 5}f(x) = 14. Note that f(5)=14, so this proves that f is continous at x=5.

3 0
3 years ago
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