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mr Goodwill [35]
2 years ago
5

Sophie gets an allowance of $15.00 each month plus an extra $2.00 for each chore she completes around the house. Which of the fo

llowing statements is correct about the amount of allowance Sophie is paid as a function of the number of chores she completes in a month?
Mathematics
1 answer:
Alex Ar [27]2 years ago
6 0

Answer:

Linear equation

Step-by-step explanation:

f(x) = 2x + 15

Linear because constant increase

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NEED HELP BEING TIMED
Firlakuza [10]

Answer:

Yes.

Step-by-step explanation:

This problem has some different steps, so lets break it down:

Ed has 12 glasses of punch with 120 milliliters of liquid contained each.

Therefore, Ed has 12 * 120 milliliters of liquid:

12 * 120 = 1440

Now, we need to convert to liters, because that is what Ed's possible answer unit is in. Since there are 1000 milliliters in a liter, we will divide 1440 by 1000.

1400 \: \div\: 1000 = 1.44.

Thusly, Ed is correct and the answer is  \boxed{\text{Yes}}}.

Hope this helps! Have a nice day! ((:

6 0
3 years ago
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You can drive your car for 4.5 hours at the average speed of 70 miles per hour. how far did you go?
Zigmanuir [339]

Answer:


Step-by-step explanation:

28.5


3 0
2 years ago
your banking cupcakes for the school dance and your recipe makes 24 cupcakes and needs 2 cups of milk . you need to make 288 cup
zhannawk [14.2K]
6 quarts of milk will be needed
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2 years ago
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Help ASAP please and thanks
Firlakuza [10]
The first one includes both
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2 years ago
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2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
3 years ago
Read 2 more answers
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