I like to start with changing fractions to decimals. It seems easier that way.
5/8 = 0.625 cups
Now divide 4 by 0.625
4 / 0.625 = 6.4
Noor can offer 6 cups with an extra 2/5 of a cup left. He can offer the 2/5 of a cup to a friend, so he can offer 7 friends some hot chocolate!
The values are 5i, -4, 2√2i, -16, -50i and i.
<h3>What is an imaginary number?</h3>
An imaginary number is a number that, when squared, has a negative result, and is defined by its property i² = −1 or i = √-1.
Given are numbers,
1) √-25 = √25*√-1 = 5i
2) √-2√-2 = 2i*2i = 4i² = -4
3) √-8 = √8*√-1 = 2√2i
4) (4i)² = 16*i² = -16
5) (2i)(5i)² = 2i*25i² = 50i³ = -50i
6) i²*i³*
= -1*(-i)*1 = i
Hence, The values are 5i, -4, 2√2i, -16, -50i and i.
For more reference imaginary number, click;
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The answers are following
sol1 y = x-1
sol2 y= x+ 7
sol4 y = x+4
Step-by-step explanation:
Solution 1
Here we are going put the point in the given equation ( given in the options)
If the each point satisfies any equation, that will be the relationship between x and y.
Given points are (-3,-4) , (2,1) , (5,4)
Let us take the option C as y = x -1
-4 = -3-1
1 = 2-1
4=5-1
Putting each value in the given equation we get LHS and RHS are same for all points. so, C is the answer.
Similarly, option B is the answer of Solution 2
Each point satisfies the equation y = x +7
Solution 4
y = x +4
You are requested to check the options of Q3 once.
The box has volume
11 in × 3 in × <em>x</em> in = 33<em>x</em> in³
and surface area
2 (11 in × 3 in + 11 in × <em>x</em> in + 3 in × <em>x</em> in) = (66 + 28<em>x</em>) in²
The volume and area have the same value if
33<em>x</em> = 66 + 28<em>x</em>
Solve this equation for <em>x</em> :
33<em>x</em> - 28<em>x</em> = 66
5<em>x</em> = 66
<em>x</em> = 66/5 = 13.2
