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stealth61 [152]
2 years ago
9

Mason's annual income is $42,500. He receives an increase of 3.5% every year

Mathematics
1 answer:
Marysya12 [62]2 years ago
7 0

The function that models Mason's yearly income is 42,500(1  + 0.035)^x.

Mason's income after 5 years would be $48,084.85.

<h3>What would be Mason's income after 5 years?</h3>

The function that models Mason's income is an exponential function that has the form:

p(1 + r)^x

Where:

  • r = percentage increase
  • x = number of years
  • p = present income

42,500(1  + 0.035)^x

Income after 5 years: 42,500(1  + 0.025)^5 = $48,084.85

To learn more about exponential functions, please check: brainly.com/question/26331578

#SPJ1

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Answer:

\sf C. \quad \dfrac{1}{9}

Step-by-step explanation:

<u>Addition Law for Probability</u>

\sf P(A \cup B)=P(A)+P(B)-P(A \cap B)

Given:

  \sf P(A)=\dfrac{1}{3}=\dfrac{3}{9}

  \sf P(B)=\dfrac{2}{9}

  \sf P(A \cup B)=\dfrac{4}{9}

Substitute the given values into the formula and solve for P(A ∩ B):

\implies \sf P(A \cup B) = P(A)+P(B)-P(A \cap B)

\implies \sf \dfrac{4}{9} = \sf \dfrac{3}{9}+\dfrac{2}{9}-P(A \cap B)

\implies \sf P(A \cap B) = \sf \dfrac{3}{9}+\dfrac{2}{9}-\dfrac{4}{9}

\implies \sf P(A \cap B) = \sf \dfrac{3+2-4}{9}

\implies \sf P(A \cap B) = \sf \dfrac{1}{9}

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