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Ksju [112]
3 years ago
9

Select the equation that represents the line that passes through (1,7) and is parallel to y = 5x + 4

Mathematics
2 answers:
saveliy_v [14]3 years ago
5 0

Answer:

The equation that represents the line that passes through (1,7) and is parallel to y = 5x + 4 will be:

  • y=5x+2

Step-by-step explanation:

Given the equation

y = 5x + 4

Here the slope is:

m=5

as comparing with the y=mx+b, which is the slop-intercept form where m is the slope and b is the y-intercept.

As we know the point-slope form is

y-y_1=m\:\left(x-x_1\right)

y-7=5\left(x-1\right)

Add 7 to both sides

y-7+7=5\left(x-1\right)+7

y=5x+2

Therefore, the equation that represents the line that passes through (1,7) and is parallel to y = 5x + 4 will be:

  • y=5x+2
VladimirAG [237]3 years ago
3 0

Answer:

a

Step-by-step explanation:

it has to  have to same slope as the first equation so you have y=5x+b then what you do is plug in the points and solve for b. which gives you 2. so your final equation is y=5x+2

7=5+b

-5  -5

2=b

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IrinaVladis [17]

Answer:

w = 9

Step-by-step explanation:

Given

6 + (w - 10) = 5, that is

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w - 4 = 5 ( add 4 to both sides )

w = 9

8 0
3 years ago
Factor completely. -2k - k3^ - 3k^2
wlad13 [49]

Answer:

-k(k+1)(k+2)

Step-by-step explanation:

Begin to factor by using GCF by finding the greatest common factor. Here it is k.

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We will rearrange and factor the trinomial.

-k(2+k^2+3k)\\-k(k^2+3k+2)\\-k(k+1)(k+2)

6 0
3 years ago
Drag expressions into order to show a way to find 3 × 56.
lina2011 [118]
As we could "drag" these together, we could then do it the easy way.

  56
+56
+56
-------
168
------------------------

Or we could also do the following:

56*3:

6*3= 18.

Carry the one. 

5*3 = 15+1 (which was carried). = 16

(16+8) = 168





7 0
3 years ago
Read 2 more answers
The class midpoint of a class is
stiv31 [10]

Answer:

The center of that class, which is the sum of its largest and smallest values divided by 2 ⇒ E

Step-by-step explanation:

* Lets explain what is the class mid-point

- It is defined as the average of the upper and lower class limits

- The class midpoint is the lower class limit plus the upper class limit

 divided by 2

- The easiest way to find the class mid-point is to add the upper

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- The lower limit for every class is the smallest value in that class.

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* <u><em>Lets solve the problem</em></u>

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3 0
3 years ago
I think #1 is wrong but i can't figure it out​
goldenfox [79]

Answer:

the mistake is x and y x is 6 and y is 4 so it would be 5x6 and 4^2 divide by 2

Step-by-step explanation:

the right one is 5x-y^2 divide 2

                           5x6-4^2 divide 2

                            5x6-16 divide 2

                             30-8

                                 22

5 0
4 years ago
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