If the angle G is moved to a different spot in the circle the angle FGH and angle FEH in the cyclic quadrilateral will change to make it supplementary.
<h3 /><h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is quadrilateral inscribed in a circle. It has all its vertices on the circumference of the circle.
Opposite angles in a cyclic quadrilateral are supplementary angles. That means they add up to 180 degrees.
Therefore, if he adjust point G to a different spot on the circle, angle FGH and FEH will adjust to become supplementary.
learn more on cyclic quadrilateral here: brainly.com/question/27884509
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Answer:
0
Step-by-step explanation:hope this helped lol hope u have a wonderful thanksgiving day!!!!!!!
Answer: -4z
Step-by-step explanation:
If you subtract -3 by one, these negatives add up to be -4, making it -4z.
Answer:
y=1/2x-3
gradient = 1/2
also should satisfy the given coordinates
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
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a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
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b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
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c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
