1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zepelin [54]
3 years ago
13

What is the slope of the line parallel to a line that passes through the points L(0, 5) and Q(4, -5)

Mathematics
2 answers:
siniylev [52]3 years ago
5 0

Answer:

5/2

Step-by-step explanation:

As we go from point L(0, 5) to point Q(4, -5), x increases by 4 and y decreases by 10.  Thus, the slope of this line is m = rise / run = 10/4, or m = 5/2.  This 5/2 is also the slope of any line parallel to this one.

Oksanka [162]3 years ago
4 0

B

Using 2 points (x1,y1) (x2,y2): Slope is defined as (y2-y1)/(x2-x1)

So in this case (-5-5)/(4-0) = -10/4 which simplifies to -5/2 or B

You might be interested in
An economist for a sporting goods company estimates the revenue and cost functions for the production of a new snowboard. These
Vladimir79 [104]

Answer:

Between 1000 and 5000 snowboards will make the function AP(x) >0.

Step-by-step explanation:

Since x can only take possitive values, we have that AP(x) = P(x)/x > 0 if and only if P(x) > 0.

In order to find when P(x) > 0, we find the values from where it is 0 and then we use the Bolzano Theorem.

P(x) = R(x) - C(x) = -x²+10x - (4x+5) = -x²+6x - 5. the roots of P can be found using the quadratic formula:

r_1,r_2 = \frac{-6 ^+_- \sqrt{6^2-4*(-1)*(-5)} }{2*(-1)} = \frac{-6^+_-\sqrt{16}}{-2} = \{1, 5\}

Therefore, P(1) = P(5) = 0. Lets find intermediate values to apply Bolzano Theorem:

  • P(0) = -5 < 0 ( P is negative in (-∞ , 1) )
  • P(2) = -4+6*2-5 = 3 > 0 (P is positive in (1,5) )
  • P(6) = -36+36-5 = -5 < 0 (P is negative in (5, +∞) )

The production levels that make AP(x) >0 are between 1000 and 5000 snowboards (because we take x by thousands)

5 0
3 years ago
Which is longer 2 meters or 200 cent a meters or 2.05 meters
Yuri [45]
Solving this requires use of conversions

we already know that
2.05 m > 2 m

all that's left is the question
200 cm vs. 2.05 meters

I we know our equivalencies, we know that
100 cm = 1 m

if this is so then
200 cm = 2 m

we already know that
2.05 m > 2 m

so it must also be that
2.05 m > 200 cm

2.05 \: meters
6 0
3 years ago
Can someone help with this math question please
katrin2010 [14]
The answer is b

hope this helps :)
5 0
3 years ago
Read 2 more answers
HELP ILL AWARD BRAINLIEST
Leokris [45]

Answer:

7. 10 8. 20 9. 100 thats all i know

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A recipe for brownies calls for 2/3 Cup of chocolate chips for a batch of two dozen brownies. How many chocolate chips will be n
vovikov84 [41]

Answer:

6 cups

Step-by-step explanation:

(18  \times \frac{2}{3} ) \div 2 =

12 \div 2 =

6

8 0
3 years ago
Other questions:
  • What is the slope of the line that passes through the points
    8·1 answer
  • The function f(x) = -2x5 + x3 − 7x is an odd function. Which rule is satisfied by this function?
    9·1 answer
  • The length of a rectangle is 6 yd longer than its width. if the perimeter of the rectangle is 44 yd , find its area.
    8·1 answer
  • On a $500 loan, Carla paid $60 interest at a rate of 8%. How long did she have the loan?
    10·1 answer
  • If a right triangle has equal legs, and the hypotenuse is 26 ft. how long is each leg (leave answer in radical form)
    15·2 answers
  • 0.96 in fraction form
    12·1 answer
  • Can someone help me with question F and provide an explanation?
    6·2 answers
  • 3/5-1/7= Explain using words and numbers how you used common denominators to subtract the fractions.
    11·1 answer
  • on a tv game show,omar needs answer 7 out of every 10 questions correctly. There will be 30 questions in all
    12·1 answer
  • Simplify.<br> (-2)^-3<br><br> A.) 8<br><br> B.) 1/8<br><br> C.) -8<br><br> D.) - 1/8
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!