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zepelin [54]
2 years ago
13

What is the slope of the line parallel to a line that passes through the points L(0, 5) and Q(4, -5)

Mathematics
2 answers:
siniylev [52]2 years ago
5 0

Answer:

5/2

Step-by-step explanation:

As we go from point L(0, 5) to point Q(4, -5), x increases by 4 and y decreases by 10.  Thus, the slope of this line is m = rise / run = 10/4, or m = 5/2.  This 5/2 is also the slope of any line parallel to this one.

Oksanka [162]2 years ago
4 0

B

Using 2 points (x1,y1) (x2,y2): Slope is defined as (y2-y1)/(x2-x1)

So in this case (-5-5)/(4-0) = -10/4 which simplifies to -5/2 or B

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What is the slope of a line that passes through (6,4) and (-1, 3)
pshichka [43]

Answer:

C) 1/7

Step-by-step explanation:

so idk what the formula is called but it looks like this:

y2-y1/x2-x1 and if you plug in the numbers then you'll get the answer

3 - 4/-1 - 6 = -1/-7 = 1/7

you can also switch the numbers your answer will always be the same

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Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the
VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

\lim_{x \to 2} f(x) = 1

\lim_{x \to 2} g(x) = -4

\lim_{x \to 2} h(x) = 0

a) Applying properties of limits

\lim_{x \to 2} f(x) + 5g(x) =  \lim_{x \to 2} f(x) + 5  \lim_{x \to 2} g(x) = 1 + 5*-4 = -19

b) Applying properties of limits

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c) Applying properties of limits

\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1

d) Applying properties of limits

\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16

e) Applying properties of limits

\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0

f) Applying properties of limits

\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0

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3 years ago
Francine and Cheryl received equal scores on a test made up of multiple choice questions and an essay Francine got 34 multiple c
dem82 [27]

Answer: 2 points

Step-by-step explanation:

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Leslie ran a total of 8 miles over the course of 4 track practices. How many miles would Leslie have ran after 5 track practices
Colt1911 [192]

Answer:

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Step-by-step explanation:

Find how much she runs during one track practice by dividing 8 by 4. This gives you the equation 2x, with x being the number of track practices.

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