As we go from point L(0, 5) to point Q(4, -5), x increases by 4 and y decreases by 10. Thus, the slope of this line is m = rise / run = 10/4, or m = 5/2. This 5/2 is also the slope of any line parallel to this one.
V^2/(1-v^2/c^2)=R v^2=R(1-v^2/c^2) v^2=R-Rv^2/c^2 v^2-Rv^2/c^2=R v^2(1-R/c^2)=R v=sqrt(R/(1-R/c^2)) where R was original right side, dont forget plus minus
