All categories

2 years ago

Using bod rulemark me as brainist

Mathematics

1 answer:

faltersainse [42]2 years ago

7 0

Hello there! Moumocl here. Now want to help you .

3 + 4 - ( 6 × 2 )

3 + 4 - 12

7 - 12

-( 12-7 )

- 5ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ

( 4 × 3 ) + 6 - ( 2 ÷ 2 )

12 + 6 - 1

18 - 1

17ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ ᅠᅠᅠ

( 10 ÷ 5 ) + 6 - 2

2 + 6 - 2

8 - 2

#Hopethishelp

_____

Moumocl!

You might be interested in

What’s the answer (number 5)

sineoko [7]

80 x 3/10 = 240/10 = 24 times

6 0

4 years ago

SOMEONE PLEASE HELP ME ON QUESTIONS 17-19 I NEED ASAP

Lana71 [14]

Answer:

17. 10x+24 OR 108 18. 72 19. 8.4

Step-by-step explanation:

(10x+24)+72=180

10x+96=180

10x=84

x=8.4

10x+24

10(8.4)+24

84+24

108

8 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

Sum to n terms the series 7 +77 +777

julia-pushkina [17]

Answer:

Step-by-step explanation:

=7 (1+11+111+1111......n)

=7/9 (9+99+999+9999....n)

=7/9 ((10-1)+(10^2-1)+(10^3-1)+....n)

=7/9 ((10+10^2+10^3...n)-(1+1+1+1.....n))

=7/9 ((10 (10^n-1)/(10-1))-n)

4 0

3 years ago

Nathan had an infection, and his doctor wanted him to take penicillin. Because Nathan's father and paternal grandfather were all

RUDIKE [14]

Nathan has a 25% chance of NOT being allergic to the drug. And then that 25% is 98% accurate so:

25% x 98%

0.25 x 0.95 (changed to decimals)

= B) 0.2450

8 0

3 years ago

Using bod rulemark me as brainist​

Using bod rulemark me as brainist