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MA_775_DIABLO [31]
3 years ago
6

Write 7,000+600+10+2 in standard form

Mathematics
2 answers:
Allisa [31]3 years ago
8 0
6,612 is the answer because all you need to do is combine them by their place value.
Temka [501]3 years ago
3 0
7,612 is the answer in standard form
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The card is a two given that it is black. What is the probability ( the standard deck is 52 cards)
Ira Lisetskai [31]
If I understand the question correctly the the probability would be 2/52 or simplified 1/26
3 0
2 years ago
A. y=8x+0<br> b. x=0<br> c. y=0x +8<br> d. x=8<br> PLEASE ANSWER ASAP!!
ki77a [65]

Answer:

option d. x = 8

Step-by-step explanation:

8 0
3 years ago
Solve the equation. <br> |x + 5| = 9<br><br> a. |-14,4|<br> b. |-4,14|<br> c. |4,14|<br> d. |-14,4|
Grace [21]

Answer:

x = 4            x = -14

Step-by-step explanation:

|x + 5| = 9

The absolute value equation has a positive and negative solution

x+5 = 9   x+5 = -9

Subtract 5 from each side

x+5-5 = 9-5   x+5-5 = -9-5

x = 4            x = -14

8 0
3 years ago
Read 2 more answers
Expand and simplify 2(5x+4)+3(2x-1)
stepladder [879]

2(5x+4)+3(2x-1)

Use the distributive property for both sets of parenthesis:

2(5x+4) = 2*5x + 2*4 = 10x+8

3(2x-1) = 3*2x - 3*1 = 6x-3

Now you have:

10x+8 + 6x-3

Now combine like terms:

10x + 6x = 16x

8-3 = 5

The final answer is 16x+5

8 0
3 years ago
2x-5y+7z=6 ,x-3y+4z=3,3x-8y+11z=11. using gauss jordan method that is the answer​
Mekhanik [1.2K]

Eliminate <em>x</em> by taking two equations at a time and combining them in the the right parts.

For example, taking the first two equations, we can eliminate <em>x</em> by subtracting 2 times the second equation away from the first:

(2<em>x</em> - 5<em>y</em> + 7<em>z</em>) - 2 (<em>x</em> - 3<em>y</em> + 4<em>z</em>) = 6 - 2×3

(2<em>x</em> - 2<em>x</em>) + (-5<em>y</em> + 6<em>y</em>) + (7<em>z</em> - 8<em>z</em>) = 6 - 6

<em>y</em> - <em>z</em> = 0

Similarly, take 3 times the second equation from the third:

(3<em>x</em> - 8<em>y</em> + 11<em>z</em>) - 3 (<em>x</em> - 3<em>y</em> + 4<em>z</em>) = 11 - 3×3

(3<em>x</em> - 3<em>x</em>) + (-8<em>y</em> + 9<em>y</em>) + (11<em>z</em> - 12<em>z</em>) = 11 - 33

<em>y</em> - <em>z</em> = -22

But these two new equations say 0 = -22, which is not true. So there is no solution to this system.

6 0
2 years ago
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