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user100 [1]
3 years ago
11

Which number sentence is true?

Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0

Answer:

B

Step-by-step explanation:

BECAUSE THE ABSOLUTE VALUE CHANGE ANY NUMBER TO POSITIVE SO CERO IS EQUAL TO CERO.

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Five consecutive numbers have a sum of 110.<br> What is the least of these consecutive<br> numbers
valentinak56 [21]

Answer:

8

Step-by-step explanation:

8. If the sum of five consecutive even integers is 110, what is the least of these integers? Explanation: 18 Since these numbers are "evenly spaced," their mean (average) is equal to their median (middle number).

5 0
3 years ago
Paula bought a ski jacket on sale for $7 less than half its original price. She paid $84 for the jacket. What was the original p
Eddi Din [679]
1/2x - 7 = 84
1/2x = 84 + 7
1/2x = 91
x = 91 / (1/2)
x = 91 * 2
x = 182 <=== original price
5 0
3 years ago
PLEASE CAN SOMEONE HELP ME WITH THE 3 QUETIONS
VARVARA [1.3K]
1.
2x (4x² -3x +8) - (3x+4)
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8x³ -6x² +13x -4


2.
3x(2x²-7)+7x(x²+4)
6x³ -21x +7x³ +28x
13x³ +7x


3.
2x² (-4x^4 -12x² - x +17)
-8x^6 - 24x^4 - 2x³ + 34x²
3 0
4 years ago
If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=
Alexxx [7]
\bf f(x)=y=2x+sin(x)&#10;\\\\\\&#10;inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)&#10;\\\\\\&#10;\textit{now, the "y" in the inverse, is really just g(x)}&#10;\\\\\\&#10;\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\&#10;-----------------------------\\\\

\bf \textit{let's use implicit differentiation}\\\\&#10;1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}&#10;\\\\\\&#10;1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\&#10;-----------------------------\\\\&#10;g'(2)=\cfrac{1}{2+cos[g(2)]}

now, if we just knew what g(2)  is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that  means if we use that value in f(x),   f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus    2 = 2x+sin(x)

\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2&#10;\\\\\\&#10;-----------------------------\\\\&#10;g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it
5 0
3 years ago
Help please? not sure about this
zimovet [89]

9514 1404 393

Answer:

  72 kph

Step-by-step explanation:

The first sentence tells you the speeds are proportional. So, you can write the proportion ...

  kph/mph = 120/75 = x/45

Multiplying by 45 gives x:

  x = (45)(120/75) = 72

72 kph is 45 mph.

8 0
3 years ago
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