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2 years ago

Find the distance between the origin and the point (-12,5). A. 12 B. 6 C. 7 D. 13

Mathematics

2 answers:

Neporo4naja [7]2 years ago

8 0

Answer:

I'd pick 13

Step-by-step explanation:

Let M (-12,5) be the given point and O (0,0) be the origin.

AlexFokin [52]2 years ago

7 0

Answer:

D. 13

Step-by-step explanation:

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SashulF [63]

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3 years ago

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Lapatulllka [165]

Answer:

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Step-by-step explanation:

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3 years ago

What is the product of <br><br>(2x+3)(4x²-5x+6) <br><br>

Rasek [7]

Answer:

24x^3-30x^2+36x

Step-by-step explanation:

you distribute.

(2x+3)(4x^2-5x+6)

distribute the 2x first

3(4x^2*2x-5x*2x+6*2x)

then simplify

3(8x^3-10x^2+12x)

then distribute again (I'm distributing and multiplying it out in this step)

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3 0

2 years ago

What is the perimeter of the triangle? Round to the nearest tenth.

Cerrena [4.2K]

Answer: 19.8 Units

Step-by-step explanation:

The triangle is shown in the attached figure, and have three vertices: $AB$ , $AC$ and $BC$ .

Each vertice represents a point in the cartesian plane and the length of each side of the triangle is the modulus of each vector.

In this sense, the modulus $m$ is calculated as shown:

$m=\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$

Hence, for each vector:

$AB=\sqrt{(-2-3)^{2} + (3-0)^{2}}=\sqrt{34}$

$AC=\sqrt{(-2-(4))^{2} + (3-(-3))^{2}}=\sqrt{40}$

$BC=\sqrt{(-4-3)^{2} + (-3-0)^{2}}=\sqrt{58}$

Now, the perimeter of a triangle is the sum of its three sides:

$AB+AC+BC=\sqrt{34} + \sqrt{40} + \sqrt{58}$

Finally:

$AB+AC+BC=19.77 \approx 19.8$

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3 years ago

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il63 [147K]

I got -2(2x-3) but it should be C.-4x-2

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2 years ago