All categories

2 years ago

Is the graph a linear function , nonlinear , function , or relation

Mathematics

1 answer:

Irina-Kira [14]2 years ago

6 0

It is a linear function , Option A is the right answer.

The missing graph is attached with the image

<h3>What is a Linear Function ?</h3>

A linear function is a function that can be represented by the equation

y = mx +c

where m is the slope and the c is the intercept on y axis.

From the graph it can be seen that it is following a straight line pattern and therefore it can be represented by y = mx +c and

Therefore it is a linear function , Option A is the right answer.

To know more about Linear Function

brainly.com/question/21107621

#SPJ1

You might be interested in

Need an answer, please need an answer, please

inna [77]

Answer:

Step-by-step explanation:

3x² - 11x - 4 = 0

a = 3 ; b = -11 , c = -4

$Sum \ of \ roots = \dfrac{-b}{a}=\dfrac{-(-11)}{3}=\dfrac{11}{3}\\\\Product \ of \ roots =\dfrac{c}{a}=\dfrac{-4}{3}\\\\$

8x² + 12x = -1

8x² + 12x + 1 = 0

a = 8 ; b = 12 ; c = 1

$Sum \ of \ roots =\dfrac{-b}{a}=\dfrac{-12}{8}=\dfrac{-3}{2}\\\\Product \ of \ roots = \dfrac{c}{a}=\dfrac{1}{8}$

x² + x = 6

x² + x - 6 = 0

a = 1 ; b= 1 ; c = -6

$Sum \ of \ roots = \dfrac{-1}{1}=-1\\\\Product \ of \ roots = \dfrac{-6}{1}=-6$

x²- 2x - 2 =0

a = 1 ; b = -2 ; c = -2

$Sum \ of \ roots = \dfrac{-(-2)}{1}=2\\\\Product \ of \ roots = \dfrac{-2}{1}=-2$

4x - 5 = -4x²

4x² + 4x - 5 = 0

a = 4 ; b = 4 ; c = -5

$Sum \ of \ roots = \dfrac{-4}{4}=-1\\\\Product \ of \ roots=\dfrac{-5}{4}$

12x² +x -6 = 0

a = 12 ; b = 1 ; c = -6

$Sum \ of \ roots =\dfrac{-1}{12}\\\\Product \ of \ roots =\dfrac{-6}{12}=\dfrac{-1}{2}$

2x² + 5x - 25 = 0

a = 2 ; b = 5 ; c = -25

$Sum \ of \ roots=\dfrac{-5}{2}\\\\Product \ of \ roots =\dfrac{-25}{2}$

6x² -5x - 4 = 0

a = 6 ; b = -5 ; c = -4

$Sum \ of \ roots =\dfrac{-[-5]}{6}=\dfrac{5}{6}\\\\Product \ of \ roots = \dfrac{-4}{6}=\dfrac{-2}{3}$

8 0

2 years ago

Read 2 more answers

How do you work out nth term

Mnenie [13.5K]

Answer:

plug in "n" in the formula to get an answer

Step-by-step explanation:

7 0

3 years ago

In a clinical trial of 268 subjects treated with a drug, 11% of the subjects reported dizziness. The margin of error is plus o

Mariulka [41]

Answer:

$\hat p =0.11$ represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

$\hat q = 1-\hat p = 1-0.11= 0.89$ represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

$\alpha= 1-0.90 =0.1$ and this value represent the significance level of the test or the probability of error type I

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The margin of error is given by:

$ME= z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

$Lower= 0.11-0.04 = 0.07$

$Upper= 0.11+0.04 = 0.15$

And for this case we have the following info:

$\hat p =0.11$ represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

$\hat q = 1-\hat p = 1-0.11= 0.89$ represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

$\alpha= 1-0.90 =0.1$ and this value represent the significance level of the test or the probability of error type I

4 0

3 years ago

Write the standard form of the line that contains a y-intercept of -3 and passes through the point (3, 0). Include your work in

mina [271]

We have two points, (3,0) and (0,-3). So we can find the slope of the line:

m=(y2-y1)/(x2-x1)

m=(-3-0)/(0-3)

m=-3/-3

m=1 so far for the line y=mx+b we have:

y=x+b, b is the y intercept which we were told is -3 so

y=x-3

The above is called the slope-intercept form of a line, y=mx+b, the standard form of a line is ax+by=c, so we need to get both variables on one side of the equation..

y=x-3 subtract x from both sides

-x+y=-3

While the above may be acceptable to some, technically the coefficient of x should be expressed as a positive value, so we should divide the above "solution" by -1 to get:

x-y=3

6 0

3 years ago

Use complete sentences to describe the transformation that maps ABCD onto its image.

Lapatulllka [165]

General Idea:

When a point or figure on a coordinate plane is moved by sliding it to the right or left or up or down, the movement is called a translation.

Say a point P(x, y) moves up or down ' k ' units, then we can represent that transformation by adding or subtracting respectively 'k' unit to the y-coordinate of the point P.

In the same way if P(x, y) moves right or left ' h ' units, then we can represent that transformation by adding or subtracting respectively 'h' units to the x-coordinate.

P(x, y) becomes $P'(x\pm h, y\pm k)$ . We need to use ' + ' sign for 'up' or 'right' translation and use ' - ' sign for ' down' or 'left' translation.

Applying the concept:

The point A of Pre-image is (0, 0). And the point A' of image after translation is (5, 2). We can notice that all the points from the pre-image moves 'UP' 2 units and 'RIGHT' 5 units.

Conclusion:

The transformation that maps ABCD onto its image is translation given by (x + 5, y + 2),

In other words, we can say ABCD is translated 5 units RIGHT and 2 units UP to get to A'B'C'D'.

6 0

3 years ago