We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
</span>- 1/(2-c)=-1/-(c-2)=1/(c-2)
(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)
(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14
the solution is c=14
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or
<span>all real numbers except c=-2 and c=2</span>
<span>Which shapes are topologically equivalent to Choice 2? D. NONE
Choice 1, 3, and 4 are topologically equivalent. These figures each have two holes.
Choice 2 has three holes and is different from the other.
Topologically equivalent figures are figures that can be rearranged to form another shape without breaking.</span>
Probability=13/52*12/51*11/50*10/49=11/4165
Answer:
I say C. Because 2 shows up twice for the bag of beans
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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