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kap26 [50]
3 years ago
6

What is 30% of 70 feet

Mathematics
2 answers:
ira [324]3 years ago
8 0
p\%=\dfrac{p}{100}\\\\30\%=\dfrac{30}{100}=0.3\\\\30\%\ of\ 70ft\ is\ 0.3\cdot70ft=21ft
marusya05 [52]3 years ago
4 0
Here : (30x70)/100= 21
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There are three times as many fiction books as non-fiction books in a library. 122 fiction books and 24 non-fiction books are lo
Alexxx [7]

Answer:

176 books

Step-by-step explanation:

Let's call the number of fiction books 'F', and the number of non-fiction books 'N'. Then, we can write the following system of equations:

eq1:

F = 3N

eq2:

2*(F - 122) = (N - 24)

2F - 244 = N - 24

2F = N + 220

Using the 'F' value from the first equation, we have:

6N = N + 220

5N = 220

N = 44\ books

F = 3N = 132\ books

The total number of books is:

F + N = 132 + 44 = 176\ books

5 0
3 years ago
Choose the property used to rewrite the expression. log618-log66 = log63.a) Commutative Propertyb) Product Propertyc) Power Prop
n200080 [17]

Answer:

Option d) is correct

ie, quotient property

Step-by-step explanation:

Given expression is log 618-log 66=log 63

Now we take log 618-log 66

log 618-log 66 = log \frac{618}{66} [By using quotient property, log\frac{x}{y}=\log x- \log y]

= log 63

Therefore log 618- log 66= log 63

Option d) is correct

In the given expression we are using the quotient property

3 0
3 years ago
Timmy has 13 dollars in his bank account he withdrew m amount of dollars. He is now 100 dallors in debt. How much
Gekata [30.6K]

Answer:

$113

Step-by-step explanation:

Since he had $13 and now he is $100 in debt:

First, he withdrew $13 to get $0 in his bank account.

He then withdrew $100 to get -$100 in his bank account.

13 + 100 = 113

8 0
3 years ago
Read 2 more answers
Find the equation of a line with the following characteristics: slope=1/2;goes through (4,-1)​
gizmo_the_mogwai [7]

Answer:

the answer is 9 14

Step-by-step explanation:

it's correct so then nine times blah equals 9 / 14

3 0
3 years ago
Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)
Wittaler [7]

(tanθ + cotθ)² = sec²θ + csc²θ

<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ

<u>Evaluate middle term</u>: 2tanθcotθ = 2*\frac{sin\theta}{cos\theta}*\frac{cos\theta}{sin\theta} = 2

⇒ tan²θ + 2+ cot²θ

= tan²θ + 1 + 1 + cot²θ

<u>Apply trig identity:</u>  tan²θ + 1 = sec²θ

⇒ sec²θ + 1 + cot²θ

<u>Apply trig identity:</u>  1 + cot²θ = csc²θ

⇒ sec²θ + csc²θ

Left side equals Right side so equation is verified


7 0
3 years ago
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