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algol13
3 years ago
13

Which is the best definition of a solution?

Chemistry
1 answer:
hichkok12 [17]3 years ago
8 0
C. A solution is any two liquids mixed.<span />
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PLEASE HELP
Arlecino [84]

Answer:

the answer is c

Explanation:

7 0
3 years ago
Page 705 #12/#13: Use the changes in oxidation numbers to identify which atom is oxidized, reduced, the oxidizing agent, and the
guapka [62]

Concepts to understand before solving:

-Oxygen is ALWAYS reduced

-OIL- Oxidation Is Loss of electrons

-RIG- Reduction Is Gain of electrons

-the element that is oxidized is the reducing agent

-the element that is reduced is the oxidizing agent

A. 2H2 + O2 —> 2H2O

O is reduced, making it the oxidizing agent

H is oxidized, making it the reducing agent

B. 2KNO3 —> 2KNO2 + O2

O is reduced, making it the oxidizing agent

KNO is oxidized, making it the reducing agent

7 0
4 years ago
Sodium metal (Na) reacts explosively with water to form sodium hydroxide (NaOH) and hydrogen gas. How many moles of sodium are n
Sati [7]

Answer:

308 moles of sodium

Explanation:

The balanced equation for the chemical reaction between sodium metal (Na) and water (H₂O) is the following:

2 Na(s) + 2 H₂O → 2 NaOH(aq) + H₂(g)

From the equation, we can see that 2 moles of Na react with 2 moles of H₂O to give 2 moles of NaOH and 1 mol of H₂ (hydrogen gas). So the stoichiometric mole ratio between Na and H₂ is: 2 mol Na/1 mol H₂. Thus, we multiply the mole ratio by the moles of H₂ to be produced to obtain the moles of Na required:

moles of Na required =  2 mol Na/1 mol H₂ x 154 moles H₂ = 308 moles Na

Therefore, 308 moles of sodium are needed to produce 154 moles of hydrogen gas.

7 0
3 years ago
What is the mole ratio of PCl3 to PCl5?
Ray Of Light [21]
It 1:1 I had an online review and thats the answer it told me it was.
-Hope this helped you
8 0
3 years ago
Read 2 more answers
Use the following equation to answer the questions and please show all work.
DIA [1.3K]

Answer:

a.36 g of water is produced.

b.64 g of O_{2} is consumed.

Explanation:

The reaction is 2H_{2} + O_{2}⇒2H_{2}O

a.

Given,

Weight of H_{2} reacted = 4g

Weight of 1 mole of H_{2} = 2\times1 = 2g

Therefore no. of moles of H_{2} reacted = \frac{4}{2} = 2 moles;

Also given,

Weight of O_{2} reacted = 32 g

Weight of 1 mole of O_{2} = 2\times16 = 32 g

Therefore no. of moles of O_{2} reacted = \frac{32}{32} = 1

We know that 2 moles of Hydrogen reacts with 1 mole of Oxygen to give 2 moles of water,

As we took 2 moles of Hydrogen and 1 mole of Oxygen,

Directly,from the equation we can tell 2moles of water will be produced.

Therefore no. of moles of H_{2} O produced = 2

Weight of 1 mole of water = 2\times 1+16 = 18

Therefore weight of H_{2}O produced = 2\times 18 = 36gm

b.

Given ,

72 g of H_{2}O is produced.

So,

no. of moles of H_{2}O produced =\frac{72}{18} = 4 moles

From equation For every 2 moles of water formed , 1 mole of oxygen must be required.

So for producing 4 moles of water,

No. of moles of Oxygen required = 2 moles.

Therefore weight of O_{2} reacted = 2\times32 = 64 g

Method 2:

Given,

8 g of H_{2} has reacted.

So,

no. of moles of H_{2} reacted = \frac{8}{2} = 4 moles.

From equation , we know that For every 2 moles of H_{2} reacted,1 mole of O_{2} will react.

Therefore,

No. of moles of O_{2} that reacts with 4 moles of H_{2} = 2\times1 = 2 moles

Therefore the weight of O_{2} reacted = 2\times 32 = 64 g

6 0
3 years ago
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