Answer: m = 0.42; Tb = 79°
Explanation: The relationship between boiling point of the solvent above a solution is directly proportional to the molal concentration of the solute, i.e.:
ΔT = 
where
ΔT is the change in boiling point of the solvent;
is the molal boiling point elevation constant;
m is the molal concentration of the solute in the solution;
For there two solutions:
1) Ethanol:
ΔT = 
Tb - 
Tb - 78.4 = 1.22.m (1)
2) Carbon Tetrachloride:
Tb - 
Tb - 76.8 = 5.03.m (2)
Solving the system of equations:
Tb - 78.4 = 1.22.m
Tb = 1.22.m + 78.4 (3)
Substituing (3) in (2)
1.22.m + 78.4 - 76.8 = 5.03m
3.81m = 1.6
m = 0.42
With m, find Tb:
T - 76.8 = 5.03.0.42
T = 2.11 + 76.8
T = 79°
<u>Molal</u> concentration is <u>0.42</u> and boiling point is 79°
Answer:
speed and how slidey things are
Explanation:
Answer:
One mole of copper atoms has Avogadro number of copper atoms i.e. 6.022×10
23
atoms.
Given the mass of Copper is 6.4g
Number of Copper atoms in 6.4g =
molar mass
given mass
×Avogadro number
=
63.55
6.4
×6.022×10
23
copper atoms
=6.064×10
22
copper atoms
Explanation:
Answer:
Following are the explanation to this question:
Explanation:
The salts of carboxylate are named by the writing, which is also named as the creation of the first, which is followed by the name of the carboxylic acid were '-ic' of the acid end and replaced by the 'ate'.
Following are the description of the given reaction:
In reaction A:
2-Bromopropanoic acid= 
⇄ 
The IUPAC name is Sodium-2-Bromopropanate
In reaction B:
2-Methylhexanoic acid= 
⇄ 
The IUPAC name is Sodium-2-Methyl hexanoate
Answer:
0.008 moles of gas are present
Explanation:
Given data:
Volume of gas = 1.75 L
Number of moles = ?
Temperature of gas = 58°C
Pressure of gas = 12.5 KPa
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
58+273 = 331 K
Pressure = 12.5/101 = 0.12 atm
by putting values in formula:
0.12 atm× 1.75 L = n× 0.0821 atm.L/ mol.K ×331 K
0.21 atm.L = n× 27.17atm.L/ mol
n = 0.21 atm.L /27.17atm.L/ mol
n = 0.008 mol