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4 years ago

Balanced chemical equation for the decomposition of solid sodium sulfide in aqueous solution.

Chemistry

1 answer:

Oliga [24]4 years ago

4 0

<h3>Answer:</h3>

Na₂S(s) → 2Na⁺(aq) + S²⁻(aq)

<h3>Explanation:</h3>

We need to know:

<h3>What are decomposition reactions?</h3>

Decomposition reactions are type of reactions in which a compound is broken down into two or more products.

When a soluble substance or a compound is dissolved in water it forms an aqueous solution.
When this happens the soluble compound such as ionic compounds ionizes to form ions.
This is an example of decomposition reaction, since the ionic compound decomposes it ions making it.
For example, sodium sulfide is an ionic compound that ionizes in water to form sodium and sulfide ions.

That is;

Na₂S(s) → 2Na⁺(aq) + S²⁻(aq)

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You have a sample of 75.6 g of C3H8. How many moles of C3H8 are in the sample?

dsp73

The number of moles that are contained in the given mass of propane ( $C_3H_8$ is 1.7143 moles.

<u>Given the following data:</u>

Mass of propane = 75.6 grams.

<u>Scientific data:</u>

The molar mass of propane = 44.1 g/mol.

To calculate the number of moles that are contained in the given mass of propane ( $C_3H_8$ ):

<h3>How to calculate the moles of a compound.</h3>

In this exercise, you're required to determine the number of moles of propane that are contained in the given sample:

Mathematically, the number of moles contained in a chemical compound is given by this formula:

$Number\;of\;moles = \frac{mass}{molar\;mass}$

Substituting the given parameters into the formula, we have;

$Number\;of\;moles = \frac{75.6}{44.1}$

Number of moles = 1.7143 moles.

Read more on number of moles here: brainly.com/question/3173452

3 0

3 years ago

How many moles of a gas would occupy 11.4 L at 273K and 2.00 atm?

bagirrra123 [75]

Answer:

1.02mol

Explanation:

Using the general gas equation below;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

P = 2.0 atm

V = 11.4L

T = 273K

n = ?

Using PV = nRT

n = PV/RT

n = 2 × 11.4/ 0.0821 × 273

n = 22.8/22.41

n = 1.017

n = 1.02mol

3 0

3 years ago

A. Based on the activation energies and frequency factors, rank the following reactions from fastest to slowest reaction rate, a

deff fn [24]

Answer:

A) $E_{a} = 350KJ/mol$ , $E_{a} = 50KJ/mol$ , $E_{a} = 50KJ/mol$

A = 1.5× $10^{-7}s^{-1}$ , A = 1.9× $10^{-7} s^{-1}$ , A=1.5× $10^{-7} s^{-1}$

B) 4.469

Explanation:

From Arrhenius equation

$K=Ae^{\frac{E_{a} }{RT} }$

where; K = Rate of constant

A = Pre exponetial factor

$E_{a}$ = Activation Energy

R = Universal constant

T = Temperature in Kelvin

Given parameters:

$E_{a} =165KJ/mol$

$T_{1}=505K$

$T_{2}=525K$

$R=8.314JK^{-1}mol^{-1}$

taking logarithm on both sides of the equation we have;

$InK=InA-\frac{E_{a} }{RT}$

since we have the rate of two different temperature the equation can be derived as:

$In(\frac{K_{2} }{K_{1} } )=\frac{E_{a} }{R}(\frac{1}{T_{1} } -\frac{1}{T_{2} } )$

$In(\frac{K_{2} }{K_{1} } )=\frac{165000J/mol}{8.314JK^{-1}mol^{-1} }.(\frac{1}{505} -\frac{1}{525} )$

$In(\frac{K_{2} }{K_{1} } )$ = 19846.04×7.544× $10^{-5}$ = 1.497

$\frac{K_{2} }{K_{1} }$ = $e^{1.497}$ = 4.469

6 0

3 years ago

What is the opposite of malleable?<br> A) brittle<br> B) ductile<br> C) insulative<br> D) conductive

inysia [295]

Answer:

A) brittle

Explanation:

5 0

4 years ago

What is the pH of a 0.08 M solution of Ca(OH),?

torisob [31]

Answer:

pH = 12.20

Explanation:

Ca(OH)2 is a strong base, so it dissociates completely. A 0.08 M solution of Ca(OH)2 is 0.16 M OH-, since every mole of Ca(OH)2 has 2 OH-.

Calculate pOH using [OH-] = 0.16 M

pOH = -log(0.16) = 0.80

pH = 14 - pOH = 14 - 0.80 = 12.20

4 0

3 years ago