Conduct experiments to see which hall Bounce the higher and see how they could collect data
<span>Their outer shells are filled So much that they don't need to bond or react with any other atoms.</span>
For ionic bond
The metal atom will lose electrons to form cations and the non metal atom will gain electron.egNaCl
Use the atomic weights of H and Cl to calculate the answer to
question 7. For H, it is 1. For Cl it is 35.45.
<span>The
ratio of H to Cl in HCL is 1:1. Therefore, 16.2 grams of H means that there
will be 16.2 * 35.45 grams of Cl within the resulting HCl. Therefore, the grams
of HCl will be 16.2 grams + 574.29 grams = 590.5 grams of HCl</span>
Answer:
The concentration of the pyridinium cation at equilibrium is 1.00×10⁻³ M
Explanation:
In water we have
C₅H₅NHBr + H₂O ⇒ C₅H₅NH+ + Br−
Pyridinium Bromide (C₅H₅NHBr) Dissociates Completely Into C₅H₅NH+ And Br− as such it is a strong Electrolyte.
Therefore the number of moles of positive ion produced per mole of C₅H₅NHBr is one
pH = - log [H₃O⁺] Therefore 10^-pH = [H₃O⁺] = concentration of C₅H₅NHBr
= 10⁻³ = 0.001M = concentration of C₅H₅NHBr
The concentration of C₅H₅NHBr is = 1.00×10⁻³ M to two places of decimal