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ss7ja [257]
3 years ago
14

How many miles does the car travel in 1.5 hours

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0
Unknown because speed is not listed.
SVEN [57.7K]3 years ago
8 0
Well that depends on how fast it is going. I'm going to start at 5 mph go by 5 until I get to 80 mph
5 mph= 7.5 miles
10 mph= 15 miles
15 mph= 22.5 miles
20 mph= 30 miles
25 mph= 37.5 miles
30 mph= 45 miles
35 mph= 52.5 miles
40 mph= 60 miles
45 mph= 67.5 miles
50 mph= 75 miles
55 mph= 82.5 miles
60 mph= 90 miles
65 mph= 97.5 miles
70 mph= 105 miles
75 mph= 112.5 miles
80 mph= 120 miles
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Benny is trying to learn how to ride a bike, but is terrified of falling. He did some research, and discovered that if he rides
Anestetic [448]

Answer:

a) 7.14% probability that Benny was learning to ride a bike using the training wheels

b) 28% probability that Benny was learning to ride a bike using the training wheels

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

Benny came home crying with a bruise on his knee, after falling. His mom is trying to guess how Benny was trying to learn to ride a bike.

a) Assuming that the probability that Benny was using each of these 3 methods is equal, what is the probability that Benny was learning to ride a bike using the training wheels?

So

Event A: Benny fell

Event B: Benny was using training wheels.

The probability that Benny was using each of these 3 methods is equal

This means that P(B) = \frac{1}{3}

He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;

This means that P(A|B) = 0.1

Probability of falling:

1/3 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.

1/3 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5

1/3 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then

P(A) = \frac{0.1 + 0.5 + 0.8}{3} = 0.4667

So

P(B|A) = \frac{\frac{1}{3}*0.1}{0.4667} = 0.0714

7.14% probability that Benny was learning to ride a bike using the training wheels

b) Since Benny's mom knows Benny so well, she knows that the probability that he was using training wheels is 0.7, regular bike is 0.2, and unicycle is 0.1. What is the probability now that Benny fell while using the training wheels?

Similar as above, just some probabilities change.

Event A: Benny fell

Event B: Benny was using training wheels.

The probability that he was using training wheels is 0.7

This means that P(B) = 0.7

He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;

This means that P(A|B) = 0.1

Probability of falling:

0.7 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.

0.2 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5

0.1 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then

P(A) = 0.7*0.1 + 0.2*0.5 + 0.1*0.8 = 0.25

So

P(B|A) = \frac{0.7*0.1}{0.25} = 0.28

28% probability that Benny was learning to ride a bike using the training wheels

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3 years ago
Please I need help!!!<br> F 25<br> G20<br> H10<br> J28
iris [78.8K]

Answer: J) 28

Step-by-step explanation: Triangle interior angles equal 180°

5 0
2 years ago
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