I'm assuming the integral is
We have
Then substituting 
and 
, the integral transforms and reduces to
which we can rewrite as
and so
Answer:
y = 2x + 1
Step-by-step explanation:
Since you have an equation and a point, all you need to do is substitute the coordinates into the equation and then solve for the y-intercept (or "b"):
y = mx + b
y = 2x + 2
(-3, -5)
-5 = 2(-3) + b
-5 = -6 + b
-5 + 6 = b
b = 1
Now you have your final equation:
y = 2x + 1
*Remember that parallel lines have the same slope, so finding a new slope is not needed!
Answer:
x=4
Step-by-step explanation:
Answer:
x=6
Step-by-step explanation:
h(x) = -( x-2)^2 +16
We want when h(x) = 0
0 = -( x-2)^2 +16
Subtract 16 from each side
-16 = -( x-2)^2 +16-16
-16 = -( x-2)^2
Divide by -1
16= ( x-2)^2
Take the square root of each side
±sqrt(16) = sqrt(( x-2)^2 )
±4 = x-2
Add 2 to each sdie
2 ±4 = x-2+2
2+4 = x 2-4 =x
6 =x -2 =x
since time cannot be negative
x=6
